Conditions | 6 |
Paths | 4 |
Total Lines | 17 |
Code Lines | 9 |
Lines | 0 |
Ratio | 0 % |
1 | <?php |
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22 | public function set($key, $value) |
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23 | { |
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24 | if ($value !== null && !is_callable($value)) { |
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25 | throw new \InvalidArgumentException('Callback must be callable.'); |
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26 | } |
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27 | |||
28 | if (!is_string($key) && !$key instanceof TaskInterface) { |
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29 | throw new \InvalidArgumentException('Pass an instance of TaskInterface or a callback'); |
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30 | } |
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31 | |||
32 | if ($key instanceof TaskInterface) { |
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33 | parent::set($key->getName(), $key); |
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34 | return; |
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35 | } |
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36 | |||
37 | parent::set($key, new Task($key, $value)); |
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38 | } |
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39 | |||
51 | } |
Let’s assume that you have a directory layout like this:
and let’s assume the following content of
Bar.php
:If both files
OtherDir/Foo.php
andSomeDir/Foo.php
are loaded in the same runtime, you will see a PHP error such as the following:PHP Fatal error: Cannot use SomeDir\Foo as Foo because the name is already in use in OtherDir/Foo.php
However, as
OtherDir/Foo.php
does not necessarily have to be loaded and the error is only triggered if it is loaded beforeOtherDir/Bar.php
, this problem might go unnoticed for a while. In order to prevent this error from surfacing, you must import the namespace with a different alias: