| Conditions | 2 |
| Paths | 2 |
| Total Lines | 27 |
| Code Lines | 17 |
| Lines | 0 |
| Ratio | 0 % |
| 1 | <?php |
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| 31 | public function testParseAndDump($code, $expectedDump) |
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| 32 | { |
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| 33 | $parser = (new ParserFactory())->create(ParserFactory::PREFER_PHP7, new \PhpParser\Lexer\Emulative( |
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| 34 | array( |
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| 35 | 'usedAttributes' => array( |
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| 36 | 'comments', |
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| 37 | 'startLine', |
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| 38 | 'endLine', |
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| 39 | 'startTokenPos', |
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| 40 | 'endTokenPos' |
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| 41 | ) |
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| 42 | ) |
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| 43 | )); |
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| 44 | $ast = $parser->parse($code); |
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| 45 | |||
| 46 | $expressionCompiler = $this->getContext()->getExpressionCompiler(); |
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| 47 | |||
| 48 | foreach ($ast as $node) { |
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| 49 | $compiledExpression = $expressionCompiler ->compile($node); |
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| 50 | self::assertInstanceOfCompiledExpression($compiledExpression); |
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| 51 | } |
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| 52 | |||
| 53 | self::assertSame( |
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| 54 | json_encode($compiledExpression->__debugInfo()), |
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| 55 | trim($expectedDump) |
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| 56 | ); |
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| 57 | } |
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| 58 | } |
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| 59 |
If you define a variable conditionally, it can happen that it is not defined for all execution paths.
Let’s take a look at an example:
In the above example, the variable $x is defined if you pass “foo” or “bar” as argument for $a. However, since the switch statement has no default case statement, if you pass any other value, the variable $x would be undefined.
Available Fixes
Check for existence of the variable explicitly:
Define a default value for the variable:
Add a value for the missing path: