It seems like you code against a concrete implementation and not the interface Symfony\Component\Console\Output\OutputInterface as the method isVerbose() does only exist in the following implementations of said interface: Symfony\Component\Console\Output\BufferedOutput, Symfony\Component\Console\Output\ConsoleOutput, Symfony\Component\Console\Output\NullOutput, Symfony\Component\Console\Output\Output, Symfony\Component\Console\Output\StreamOutput, Symfony\Component\Consol...ts\Fixtures\DummyOutput, Symfony\Component\Console\Tests\Output\TestOutput.
Let’s take a look at an example:
interfaceUser{/** @return string */publicfunctiongetPassword();}classMyUserimplementsUser{publicfunctiongetPassword(){// return something}publicfunctiongetDisplayName(){// return some name.}}classAuthSystem{publicfunctionauthenticate(User$user){$this->logger->info(sprintf('Authenticating %s.',$user->getDisplayName()));// do something.}}
In the above example, the authenticate() method works fine as long as you just pass
instances of MyUser. However, if you now also want to pass a different implementation
of User which does not have a getDisplayName() method, the code will break.
classAuthSystem{publicfunctionauthenticate(User$user){if($userinstanceofMyUser){$this->logger->info(/** ... */);}// or alternativelyif(!$userinstanceofMyUser){thrownew\LogicException('$user must be an instance of MyUser, '.'other instances are not supported.');}}}
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types
inside the if block in such a case.
gordalina /
cachetool
Let’s take a look at an example:
In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.
Available Fixes
Change the type-hint for the parameter:
Add an additional type-check:
Add the method to the interface: