1 | <?php |
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2 | |||
3 | declare(strict_types=1); |
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4 | |||
5 | namespace Yiisoft\Db\Pgsql; |
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6 | |||
7 | use function in_array; |
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8 | |||
9 | /** |
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10 | * Structured type representation to PHP array parser for PostgreSQL Server. |
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11 | */ |
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12 | final class StructuredParser |
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13 | { |
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14 | /** |
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15 | * Converts structured (composite) type value from PostgreSQL to PHP array |
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16 | * |
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17 | * @param string $value String to convert. |
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18 | */ |
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19 | public function parse(string $value): array|null |
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20 | { |
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21 | if ($value[0] !== '(') { |
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22 | return null; |
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23 | } |
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24 | |||
25 | return $this->parseComposite($value); |
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26 | } |
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27 | |||
28 | /** |
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29 | * Parses PostgreSQL composite type value encoded in string. |
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30 | * |
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31 | * @param string $value String to parse. |
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32 | */ |
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33 | private function parseComposite(string $value): array |
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34 | { |
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35 | for ($result = [], $i = 1;; ++$i) { |
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36 | $result[] = match ($value[$i]) { |
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37 | ',', ')' => null, |
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38 | '"' => $this->parseQuotedString($value, $i), |
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39 | default => $this->parseUnquotedString($value, $i), |
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40 | }; |
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41 | |||
42 | if ($value[$i] === ')') { |
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43 | return $result; |
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44 | } |
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45 | } |
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0 ignored issues
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46 | } |
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47 | |||
48 | /** |
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49 | * Parses quoted string. |
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50 | */ |
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51 | private function parseQuotedString(string $value, int &$i): string |
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52 | { |
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53 | for ($result = '', ++$i;; ++$i) { |
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54 | if ($value[$i] === '\\') { |
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55 | ++$i; |
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56 | } elseif ($value[$i] === '"') { |
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57 | ++$i; |
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58 | return $result; |
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59 | } |
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60 | |||
61 | $result .= $value[$i]; |
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62 | } |
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0 ignored issues
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In this branch, the function will implicitly return
null which is incompatible with the type-hinted return string . Consider adding a return statement or allowing null as return value.
For hinted functions/methods where all return statements with the correct type are only reachable via conditions, ?null? gets implicitly returned which may be incompatible with the hinted type. Let?s take a look at an example: interface ReturnsInt {
public function returnsIntHinted(): int;
}
class MyClass implements ReturnsInt {
public function returnsIntHinted(): int
{
if (foo()) {
return 123;
}
// here: null is implicitly returned
}
}
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63 | } |
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64 | |||
65 | /** |
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66 | * Parses unquoted string. |
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67 | */ |
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68 | private function parseUnquotedString(string $value, int &$i): string |
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69 | { |
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70 | for ($result = '';; ++$i) { |
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71 | if (in_array($value[$i], [',', ')'], true)) { |
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72 | return $result; |
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73 | } |
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74 | |||
75 | $result .= $value[$i]; |
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76 | } |
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0 ignored issues
–
show
In this branch, the function will implicitly return
null which is incompatible with the type-hinted return string . Consider adding a return statement or allowing null as return value.
For hinted functions/methods where all return statements with the correct type are only reachable via conditions, ?null? gets implicitly returned which may be incompatible with the hinted type. Let?s take a look at an example: interface ReturnsInt {
public function returnsIntHinted(): int;
}
class MyClass implements ReturnsInt {
public function returnsIntHinted(): int
{
if (foo()) {
return 123;
}
// here: null is implicitly returned
}
}
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77 | } |
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78 | } |
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79 |
For hinted functions/methods where all return statements with the correct type are only reachable via conditions, ?null? gets implicitly returned which may be incompatible with the hinted type. Let?s take a look at an example: