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<?php
/*
Given an array, find the int that appears an odd number of times.
There will always be only one integer that appears an odd number of times.
*/
/**
* findIt
*
* @param mixed $arr
* @return int
function findIt(array $arr) : int
{
$count = 0;
$arrCount = count($arr);
for ($i = 0; $i < $arrCount; $i++)
for ($j = 0; $j < $arrCount; $j++)
if ($arr[$i] == $arr[$j]) {
$count++;
}
if ($count % 2 != 0) {
return $arr[$i];
return -1;
// Alternate solution:
* altfindIt
* @param mixed $seq
* @return mixed
function altfindIt(array $seq) : mixed
$nums = array_count_values($seq);
foreach ($nums as $key => $val) {
if ($val % 2) {
return $key;
w3bdesign /
Codewars-PHP
