Completed
Push — master ( 9573eb...833af1 )
by Amine
11s
created

SyntaxHelper::__construct()   A

Complexity

Conditions 1
Paths 1

Size

Total Lines 1
Code Lines 1

Duplication

Lines 0
Ratio 0 %

Importance

Changes 0
Metric Value
dl 0
loc 1
rs 10
c 0
b 0
f 0
cc 1
eloc 1
nc 1
nop 0
1
<?php namespace Tarsana\Command\Helpers;
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use Tarsana\Syntax\Syntax;
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class SyntaxHelper {
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    protected static $instance;
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    public static function instance() : SyntaxHelper
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    {
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        if (null === self::$instance)
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            self::$instance = new SyntaxHelper;
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        return self::$instance;
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    }
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    private function __construct() {}
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    public function type(Syntax $syntax) : string
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    {
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        $class = explode("\\", get_class($syntax));
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        return strtolower(substr(array_pop($class), 0, -6));
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    }
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    public function asString(Syntax $syntax) : string
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    {
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        $type = $this->type($syntax);
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        if ($type == 'optional')
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            return $this->asString($syntax->syntax());
0 ignored issues
show
Bug introduced by
It seems like you code against a specific sub-type and not the parent class Tarsana\Syntax\Syntax as the method syntax() does only exist in the following sub-classes of Tarsana\Syntax\Syntax: Debugger, Tarsana\Syntax\ArraySyntax, Tarsana\Syntax\OptionalSyntax. Maybe you want to instanceof check for one of these explicitly?

Let’s take a look at an example:

abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the parent class:

    abstract class User
    {
        /** @return string */
        abstract public function getPassword();
    
        /** @return string */
        abstract public function getDisplayName();
    }
    
Loading history...
30
        switch ($type) {
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            case 'object':
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                return implode(
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                    $syntax->separator(),
0 ignored issues
show
Bug introduced by
It seems like you code against a specific sub-type and not the parent class Tarsana\Syntax\Syntax as the method separator() does only exist in the following sub-classes of Tarsana\Syntax\Syntax: Tarsana\Syntax\ArraySyntax, Tarsana\Syntax\ObjectSyntax. Maybe you want to instanceof check for one of these explicitly?

Let’s take a look at an example:

abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the parent class:

    abstract class User
    {
        /** @return string */
        abstract public function getPassword();
    
        /** @return string */
        abstract public function getDisplayName();
    }
    
Loading history...
34
                    array_keys($syntax->fields())
0 ignored issues
show
Bug introduced by
It seems like you code against a specific sub-type and not the parent class Tarsana\Syntax\Syntax as the method fields() does only exist in the following sub-classes of Tarsana\Syntax\Syntax: Tarsana\Syntax\ObjectSyntax. Maybe you want to instanceof check for one of these explicitly?

Let’s take a look at an example:

abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the parent class:

    abstract class User
    {
        /** @return string */
        abstract public function getPassword();
    
        /** @return string */
        abstract public function getDisplayName();
    }
    
Loading history...
35
                );
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            break;
0 ignored issues
show
Unused Code introduced by
break is not strictly necessary here and could be removed.

The break statement is not necessary if it is preceded for example by a return statement:

switch ($x) {
    case 1:
        return 'foo';
        break; // This break is not necessary and can be left off.
}

If you would like to keep this construct to be consistent with other case statements, you can safely mark this issue as a false-positive.

Loading history...
37
            case 'array':
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                $text = $this->asString($syntax->syntax());
0 ignored issues
show
Bug introduced by
It seems like you code against a specific sub-type and not the parent class Tarsana\Syntax\Syntax as the method syntax() does only exist in the following sub-classes of Tarsana\Syntax\Syntax: Debugger, Tarsana\Syntax\ArraySyntax, Tarsana\Syntax\OptionalSyntax. Maybe you want to instanceof check for one of these explicitly?

Let’s take a look at an example:

abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the parent class:

    abstract class User
    {
        /** @return string */
        abstract public function getPassword();
    
        /** @return string */
        abstract public function getDisplayName();
    }
    
Loading history...
39
                return "{$text}{$syntax->separator()}...";
0 ignored issues
show
Bug introduced by
It seems like you code against a specific sub-type and not the parent class Tarsana\Syntax\Syntax as the method separator() does only exist in the following sub-classes of Tarsana\Syntax\Syntax: Tarsana\Syntax\ArraySyntax, Tarsana\Syntax\ObjectSyntax. Maybe you want to instanceof check for one of these explicitly?

Let’s take a look at an example:

abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the parent class:

    abstract class User
    {
        /** @return string */
        abstract public function getPassword();
    
        /** @return string */
        abstract public function getDisplayName();
    }
    
Loading history...
40
            break;
0 ignored issues
show
Unused Code introduced by
break is not strictly necessary here and could be removed.

The break statement is not necessary if it is preceded for example by a return statement:

switch ($x) {
    case 1:
        return 'foo';
        break; // This break is not necessary and can be left off.
}

If you would like to keep this construct to be consistent with other case statements, you can safely mark this issue as a false-positive.

Loading history...
41
            default:
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                return $type;
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        }
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    }
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    public function fields(Syntax $syntax) : array
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    {
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        $type = $this->type($syntax);
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        switch ($type) {
50
            case 'object':
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                return $syntax->fields();
0 ignored issues
show
Bug introduced by
It seems like you code against a specific sub-type and not the parent class Tarsana\Syntax\Syntax as the method fields() does only exist in the following sub-classes of Tarsana\Syntax\Syntax: Tarsana\Syntax\ObjectSyntax. Maybe you want to instanceof check for one of these explicitly?

Let’s take a look at an example:

abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the parent class:

    abstract class User
    {
        /** @return string */
        abstract public function getPassword();
    
        /** @return string */
        abstract public function getDisplayName();
    }
    
Loading history...
52
            case 'array':
53
            case 'optional':
54
                return $this->fields($syntax->syntax());
0 ignored issues
show
Bug introduced by
It seems like you code against a specific sub-type and not the parent class Tarsana\Syntax\Syntax as the method syntax() does only exist in the following sub-classes of Tarsana\Syntax\Syntax: Debugger, Tarsana\Syntax\ArraySyntax, Tarsana\Syntax\OptionalSyntax. Maybe you want to instanceof check for one of these explicitly?

Let’s take a look at an example:

abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the parent class:

    abstract class User
    {
        /** @return string */
        abstract public function getPassword();
    
        /** @return string */
        abstract public function getDisplayName();
    }
    
Loading history...
55
        }
56
        return [];
57
    }
58
59
}
60