Conditions | 4 |
Paths | 3 |
Total Lines | 13 |
Code Lines | 6 |
Lines | 0 |
Ratio | 0 % |
Tests | 5 |
CRAP Score | 4.3731 |
Changes | 1 | ||
Bugs | 0 | Features | 0 |
1 | <?php |
||
42 | 2 | public static function getAccessor(?ContainerInterface $container = null): Accessor |
|
43 | { |
||
44 | 2 | if ($container !== null && !$container instanceof Container) { |
|
45 | throw new \InvalidArgumentException('Container must be an instance of ' . Container::class); |
||
46 | } |
||
47 | |||
48 | 2 | $container ??= ContainerScope::getContainer(); |
|
49 | |||
50 | 2 | if (!$container instanceof Container) { |
|
51 | throw new \RuntimeException('Container is not available.'); |
||
52 | } |
||
53 | |||
54 | 2 | return new Accessor($container); |
|
55 | } |
||
57 |
Let?s assume that you have a directory layout like this:
and let?s assume the following content of
Bar.php
:If both files
OtherDir/Foo.php
andSomeDir/Foo.php
are loaded in the same runtime, you will see a PHP error such as the following:PHP Fatal error: Cannot use SomeDir\Foo as Foo because the name is already in use in OtherDir/Foo.php
However, as
OtherDir/Foo.php
does not necessarily have to be loaded and the error is only triggered if it is loaded beforeOtherDir/Bar.php
, this problem might go unnoticed for a while. In order to prevent this error from surfacing, you must import the namespace with a different alias: