Both the $myVar assignment in line 1 and the $higher assignment in line 2
are dead. The first because $myVar is never used and the second because
$higher is always overwritten for every possible time line.
Loading history...
26
foreach ($dto->oncalls as $entry) {
27
$policy = new EscalationPolicy($entry->escalation_policy);
The call to EscalationPolicy::__construct() has too many arguments starting with $entry->escalation_policy.
This check compares calls to functions or methods with their respective definitions.
If the call has more arguments than are defined, it raises an issue.
If a function is defined several times with a different number of parameters, the
check may pick up the wrong definition and report false positives. One codebase
where this has been known to happen is Wordpress.
In this case you can add the @ignorePhpDoc
annotation to the duplicate definition and it will be ignored.
$entries was never initialized. Although not strictly required by PHP, it is generally a good practice to add $entries = array(); before regardless.
Adding an explicit array definition is generally preferable to implicit array
definition as it guarantees a stable state of the code.
Let’s take a look at an example:
foreach($collectionas$item){$myArray['foo']=$item->getFoo();if($item->hasBar()){$myArray['bar']=$item->getBar();}// do something with $myArray}
As you can see in this example, the array $myArray is initialized the first
time when the foreach loop is entered. You can also see that the value of the
bar key is only written conditionally; thus, its value might result from a
previous iteration.
This might or might not be intended. To make your intention clear, your code
more readible and to avoid accidental bugs, we recommend to add an explicit
initialization $myArray=array() either outside or inside the foreach loop.
The variable $entries does not seem to be defined for all execution paths leading up to this point.
If you define a variable conditionally, it can happen that it is not defined
for all execution paths.
Let’s take a look at an example:
functionmyFunction($a){switch($a){case'foo':$x=1;break;case'bar':$x=2;break;}// $x is potentially undefined here.echo$x;}
In the above example, the variable $x is defined if you pass “foo” or “bar”
as argument for $a. However, since the switch statement has no default
case statement, if you pass any other value, the variable $x would be undefined.
Available Fixes
Check for existence of the variable explicitly:
functionmyFunction($a){switch($a){case'foo':$x=1;break;case'bar':$x=2;break;}if(isset($x)){// Make sure it's always set.echo$x;}}
Define a default value for the variable:
functionmyFunction($a){$x='';// Set a default which gets overridden for certain paths.switch($a){case'foo':$x=1;break;case'bar':$x=2;break;}echo$x;}
Add a value for the missing path:
functionmyFunction($a){switch($a){case'foo':$x=1;break;case'bar':$x=2;break;// We add support for the missing case.default:$x='';break;}echo$x;}
This check looks for variable assignements that are either overwritten by other assignments or where the variable is not used subsequently.
Both the
$myVar
assignment in line 1 and the$higher
assignment in line 2 are dead. The first because$myVar
is never used and the second because$higher
is always overwritten for every possible time line.