1 | <?php |
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30 | class Role extends Model |
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31 | { |
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32 | use Traits\Role\QueryTrait, |
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33 | Traits\Role\RelationTrait; |
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34 | |||
35 | const ROLE_USER = 'user'; |
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36 | const ROLE_DEVELOPER = 'developer'; |
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37 | const ROLE_MANAGER = 'manager'; |
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38 | const ROLE_ADMIN = 'administrator'; |
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39 | |||
40 | /** |
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41 | * Timestamp enabled. |
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42 | * |
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43 | * @var bool |
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44 | */ |
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45 | public $timestamps = false; |
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46 | |||
47 | /** |
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48 | * Name of database table. |
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49 | * |
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50 | * @var string |
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51 | */ |
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52 | protected $table = 'roles'; |
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53 | |||
54 | /** |
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55 | * Returns a class name based on role type. |
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56 | * |
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57 | * @return string |
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58 | */ |
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59 | 4 | public function className() |
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74 | } |
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75 |
Let’s assume that you have a directory layout like this:
and let’s assume the following content of
Bar.php
:If both files
OtherDir/Foo.php
andSomeDir/Foo.php
are loaded in the same runtime, you will see a PHP error such as the following:PHP Fatal error: Cannot use SomeDir\Foo as Foo because the name is already in use in OtherDir/Foo.php
However, as
OtherDir/Foo.php
does not necessarily have to be loaded and the error is only triggered if it is loaded beforeOtherDir/Bar.php
, this problem might go unnoticed for a while. In order to prevent this error from surfacing, you must import the namespace with a different alias: