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Code Duplication    Length = 26-28 lines in 3 locations

VoltCycle/baseline_version2.py 1 location

@@ 20-47 (lines=28) @@
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    return vector1, vector2
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def critical_idx(x, y): ## Finds index where data set is no longer linear 
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    """
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    This function takes x and y values callculate the derrivative of x and y, and calculate moving average of 5 and 15 points.
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    Finds intercepts of different moving average curves and return the indexs of the first intercepts.
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    """
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    k = np.diff(y)/(np.diff(x)) #calculated slops of x and y
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    ## Calculate moving average for 5 and 15 points.
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    ## This two arbitrary number can be tuned to get better fitting.
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    ave10 = []
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    ave15 = []
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    for i in range(len(k)-10):  # The reason to minus 5 is to prevent j from running out of index.
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        a = 0 
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        for j in range(0,5):
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            a = a + k[i+j]
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        ave10.append(round(a/5, 5)) # keeping 9 desimal points for more accuracy
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    for i in range(len(k)-15): 
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        b = 0 
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        for j in range(0,10):
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            b = b + k[i+j]
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        ave15.append(round(b/10, 5))
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    ave10i = np.asarray(ave5)
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    print(ave10i)
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    ave15i = np.asarray(ave15)
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    print(ave15i)
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    ## Find intercepts of different moving average curves
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    idx = np.argwhere(np.diff(np.sign(ave15i - ave10i[:len(ave15i)])!= 0)).reshape(-1)+0 #reshape into one row.
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    return idx[1]
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# This is based on the method 1 where user can't choose the baseline.
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# If wanted to add that, choose method2.

VoltCycle/main.py 1 location

@@ 147-172 (lines=26) @@
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    vector2 = np.array(vector)[split:end]
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    return vector1, vector2
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def critical_idx(x, y): ## Finds index where data set is no longer linear 
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    """
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    This function takes x and y values callculate the derrivative of x and y, and calculate moving average of 5 and 15 points.
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    Finds intercepts of different moving average curves and return the indexs of the first intercepts.
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    """
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    k = np.diff(y)/(np.diff(x)) #calculated slops of x and y
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    ## Calculate moving average for 5 and 15 points.
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    ## This two arbitrary number can be tuned to get better fitting.
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    ave5 = []
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    ave15 = []
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    for i in range(len(x)-5):  # The reason to minus 5 is to prevent j from running out of index.
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        a = 0 
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        for j in range(0,5):
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            a = a + k[i+j]
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        ave5.append(round(a/5, 5)) # keeping 9 desimal points for more accuracy
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    ave5 = np.asarray(ave5)
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    for i in range(len(x)-15): 
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        b = 0 
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        for j in range(0,15):
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            b = b + k[i+j]
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        ave15.append(round(b/15, 5))
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    ave15 = np.asarray(ave15)
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    ## Find intercepts of different moving average curves
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    idx = np.argwhere(np.diff(np.sign(ave15 - ave5[:len(ave15)])!= 0)).reshape(-1) #reshape into one row.
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    return int(idx[0])
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def mean(vector):
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    """

VoltCycle/baseline.py 1 location

@@ 24-49 (lines=26) @@
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    vector2 = np.array(vector)[split:end]
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    return vector1, vector2
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def critical_idx(x, y): ## Finds index where data set is no longer linear 
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    """
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    This function takes x and y values callculate the derrivative of x and y, and calculate moving average of 5 and 15 points.
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    Finds intercepts of different moving average curves and return the indexs of the first intercepts.
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    """
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    k = np.diff(y)/(np.diff(x)) #calculated slops of x and y
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    ## Calculate moving average for 5 and 15 points.
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    ## This two arbitrary number can be tuned to get better fitting.
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    ave5 = []
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    ave15 = []
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    for i in range(len(k)-5):  # The reason to minus 5 is to prevent j from running out of index.
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        a = 0 
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        for j in range(0,5):
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            a = a + k[i+j]
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        ave5.append(round(a/5, 4)) # keeping 9 desimal points for more accuracy
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    ave5 = np.asarray(ave5)
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    for i in range(len(k)-15): 
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        b = 0 
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        for j in range(0,15):
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            b = b + k[i+j]
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        ave15.append(round(b/15, 5))
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    ave15 = np.asarray(ave15)
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    ## Find intercepts of different moving average curves
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    idx = np.argwhere(np.diff(np.sign(ave15 - ave5[:len(ave15)])!= 0)).reshape(-1) #reshape into one row.
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    return int(idx[0])
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def mean(vector):
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    """