looking-for-a-job /
cp.py
| Conditions | 15 |
| Total Lines | 26 |
| Lines | 0 |
| Ratio | 0 % |
Complex classes like cp() often do a lot of different things. To break such a class down, we need to identify a cohesive component within that class. A common approach to find such a component is to look for fields/methods that share the same prefixes, or suffixes.
Once you have determined the fields that belong together, you can apply the Extract Class refactoring. If the component makes sense as a sub-class, Extract Subclass is also a candidate, and is often faster.
| 1 | #!/usr/bin/env python |
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| 10 | @public |
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| 11 | def cp(source,target,force=True): |
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| 12 | if isinstance(source,list): # list |
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| 13 | # copy files to dir |
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| 14 | targets = [] |
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| 15 | for s in source: |
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| 16 | t = cp(s,target,force) |
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| 17 | targets.append(t) |
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| 18 | return targets |
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| 19 | assert_exists(source) # assert exists |
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| 20 | if not force and exists(target): return |
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| 21 | if source==target: |
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| 22 | return target |
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| 23 | if isfile(source) and isdir(target): |
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| 24 | # target is DIR |
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| 25 | target = join(target,basename(source)) |
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| 26 | if isfile(source) or islink(source): |
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| 27 | if (exists(target) or lexists(target)) and isfile(source)!=isfile(target): |
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| 28 | os.unlink(target) |
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| 29 | shutil.copy(source,target) |
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| 30 | if isdir(source): |
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| 31 | # first create dirs |
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| 32 | if not exists(target): |
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| 33 | os.makedirs(target) |
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| 34 | dir_util.copy_tree(source,target) |
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| 35 | return target |
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| 36 | |||
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