| Conditions | 3 | 
| Paths | 3 | 
| Total Lines | 17 | 
| Code Lines | 9 | 
| Lines | 0 | 
| Ratio | 0 % | 
| Changes | 0 | ||
| 1 | <?php | ||
| 23 | public function generate(TaxonInterface $taxon, $locale = null) | ||
| 24 |     { | ||
| 25 | $name = $taxon->getTranslation($locale)->getName(); | ||
|  | |||
| 26 | |||
| 27 | Assert::notEmpty($name, 'Cannot generate slug without a name.'); | ||
| 28 | |||
| 29 | $slug = $this->transliterate($name); | ||
| 30 | |||
| 31 | $parentTaxon = $taxon->getParent(); | ||
| 32 |         if (null === $parentTaxon) { | ||
| 33 | return $slug; | ||
| 34 | } | ||
| 35 | |||
| 36 | $parentSlug = $parentTaxon->getTranslation($locale)->getSlug() ?: $this->generate($parentTaxon, $locale); | ||
| 37 | |||
| 38 | return $parentSlug . '/' . $slug; | ||
| 39 | } | ||
| 40 | |||
| 52 | 
Let’s take a look at an example:
In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.
Available Fixes
Change the type-hint for the parameter:
Add an additional type-check:
Add the method to the interface: