| Conditions | 3 |
| Paths | 3 |
| Total Lines | 17 |
| Code Lines | 9 |
| Lines | 0 |
| Ratio | 0 % |
| Changes | 0 | ||
| 1 | <?php |
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| 23 | public function generate(TaxonInterface $taxon, $locale = null) |
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| 24 | { |
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| 25 | $name = $taxon->getTranslation($locale)->getName(); |
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| 26 | |||
| 27 | Assert::notEmpty($name, 'Cannot generate slug without a name.'); |
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| 28 | |||
| 29 | $slug = $this->transliterate($name); |
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| 30 | |||
| 31 | $parentTaxon = $taxon->getParent(); |
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| 32 | if (null === $parentTaxon) { |
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| 33 | return $slug; |
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| 34 | } |
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| 35 | |||
| 36 | $parentSlug = $parentTaxon->getTranslation($locale)->getSlug() ?: $this->generate($parentTaxon, $locale); |
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| 37 | |||
| 38 | return $parentSlug . '/' . $slug; |
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| 39 | } |
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| 40 | |||
| 52 |
Let’s take a look at an example:
In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.
Available Fixes
Change the type-hint for the parameter:
Add an additional type-check:
Add the method to the interface: