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1 | <?php |
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2 | namespace pheme\settings; |
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3 | |||
4 | use Yii; |
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5 | use yii\base\Action; |
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6 | |||
7 | class SettingsAction extends Action |
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8 | { |
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9 | /** |
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10 | * @var string class name of the model which will be used to validate the attributes. |
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11 | * The class should have a scenario matching the `scenario` variable. |
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12 | * The model class must implement [[Model]]. |
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13 | * This property must be set. |
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14 | */ |
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15 | public $modelClass; |
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16 | |||
17 | /** |
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18 | * @var string The scenario this model should use to make validation |
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19 | */ |
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20 | public $scenario; |
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21 | |||
22 | /** |
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23 | * @var string the name of the view to generate the form. Defaults to 'settings'. |
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24 | */ |
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25 | public $viewName = 'settings'; |
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26 | |||
27 | /** |
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28 | * Render the settings form. |
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29 | */ |
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30 | public function run() |
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31 | { |
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32 | /* @var $model \yii\db\ActiveRecord */ |
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33 | $model = new $this->modelClass(); |
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34 | if ($this->scenario) { |
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35 | $model->setScenario($this->scenario); |
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36 | } |
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37 | if ($model->load(Yii::$app->request->post()) && $model->validate()) { |
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38 | foreach ($model->toArray() as $key => $value) { |
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39 | Yii::$app->settings->set($key, $value, $model->formName()); |
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40 | } |
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41 | Yii::$app->getSession()->addFlash('success', |
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42 | Module::t('settings', 'Successfully saved settings on {section}', |
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43 | ['section' => $model->formName()] |
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44 | ) |
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45 | ); |
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46 | } |
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47 | foreach ($model->attributes() as $key) { |
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48 | $model->{$key} = Yii::$app->settings->get($key, $model->formName()); |
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49 | } |
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50 | return $this->controller->render($this->viewName, ['model' => $model]); |
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51 | } |
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52 | } |
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53 |
It seems like the method you are trying to call exists only in some of the possible types.
Let’s take a look at an example:
Available Fixes
Add an additional type-check:
Only allow a single type to be passed if the variable comes from a parameter: