Completed
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by Thomas
10:01
created

UniqueEmailValidator::validate()   A

Complexity

Conditions 2
Paths 2

Size

Total Lines 8
Code Lines 6

Duplication

Lines 0
Ratio 0 %

Importance

Changes 1
Bugs 0 Features 0
Metric Value
c 1
b 0
f 0
dl 0
loc 8
rs 9.4285
cc 2
eloc 6
nc 2
nop 2
1
<?php
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namespace keeko\core\validator\constraints;
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use Symfony\Component\Validator\ConstraintValidator;
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use Symfony\Component\Validator\Constraint;
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use keeko\core\model\UserQuery;
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class UniqueEmailValidator extends ConstraintValidator {
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	public function validate($value, Constraint $constraint) {
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		$users = UserQuery::create()->findByEmail($value);
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		if (count($users) > 0) {
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			$this->context->buildViolation($constraint->message)
0 ignored issues
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Bug introduced by
It seems like you code against a concrete implementation and not the interface Symfony\Component\Valida...ecutionContextInterface as the method buildViolation() does only exist in the following implementations of said interface: Symfony\Component\Valida...ontext\ExecutionContext, Symfony\Component\Valida...\LegacyExecutionContext.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
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				->setParameter('email', $value)
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				->addViolation();
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		}
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	}
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}