EvernoteMember::getCMSFields()   A
last analyzed

Complexity

Conditions 1
Paths 1

Size

Total Lines 6
Code Lines 4

Duplication

Lines 0
Ratio 0 %

Importance

Changes 1
Bugs 0 Features 0
Metric Value
c 1
b 0
f 0
dl 0
loc 6
rs 9.4285
cc 1
eloc 4
nc 1
nop 0
1
<?php
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class EvernoteMember extends DataExtension
0 ignored issues
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Coding Style Compatibility introduced by
PSR1 recommends that each class must be in a namespace of at least one level to avoid collisions.

You can fix this by adding a namespace to your class:

namespace YourVendor;

class YourClass { }

When choosing a vendor namespace, try to pick something that is not too generic to avoid conflicts with other libraries.

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4
{
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    /**
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     * @var array
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     */
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    private static $db = array(
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Unused Code introduced by
The property $db is not used and could be removed.

This check marks private properties in classes that are never used. Those properties can be removed.

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10
        "EvernoteToken" => "Varchar(255)",
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    );
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    /**
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     * @return mixed
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     */
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    public function getCMSFields() {
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        $fields = parent::getCMSFields();
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Bug introduced by
It seems like you code against a specific sub-type and not the parent class DataExtension as the method getCMSFields() does only exist in the following sub-classes of DataExtension: EvernoteMember. Maybe you want to instanceof check for one of these explicitly?

Let’s take a look at an example:

abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the parent class:

    abstract class User
    {
        /** @return string */
        abstract public function getPassword();
    
        /** @return string */
        abstract public function getDisplayName();
    }
    
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18
        $fields->addFieldToTab('Root.Main', new TextField("EvernoteToken", 'Evernote Token', $this->EvernoteToken));
0 ignored issues
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Bug introduced by
The property EvernoteToken does not exist. Did you maybe forget to declare it?

In PHP it is possible to write to properties without declaring them. For example, the following is perfectly valid PHP code:

class MyClass { }

$x = new MyClass();
$x->foo = true;

Generally, it is a good practice to explictly declare properties to avoid accidental typos and provide IDE auto-completion:

class MyClass {
    public $foo;
}

$x = new MyClass();
$x->foo = true;
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        return $fields;
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    }
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}
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