Conditions | 3 |
Paths | 4 |
Total Lines | 11 |
Code Lines | 5 |
Lines | 0 |
Ratio | 0 % |
Tests | 5 |
CRAP Score | 3.0416 |
Changes | 0 |
1 | <?php |
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15 | 18 | protected function decodeHttpResponse($content, $unwrap = true) |
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16 | { |
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17 | 18 | if ($content instanceof TestResponse) { |
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18 | 16 | $content = $content->content(); |
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19 | } |
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20 | |||
21 | 18 | if ($unwrap) { |
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22 | 18 | return json_decode($content, true)['data'] ?? json_decode($content, true); |
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23 | } |
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24 | |||
25 | return json_decode($content, true); |
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26 | } |
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37 |
Let?s assume that you have a directory layout like this:
and let?s assume the following content of
Bar.php
:If both files
OtherDir/Foo.php
andSomeDir/Foo.php
are loaded in the same runtime, you will see a PHP error such as the following:PHP Fatal error: Cannot use SomeDir\Foo as Foo because the name is already in use in OtherDir/Foo.php
However, as
OtherDir/Foo.php
does not necessarily have to be loaded and the error is only triggered if it is loaded beforeOtherDir/Bar.php
, this problem might go unnoticed for a while. In order to prevent this error from surfacing, you must import the namespace with a different alias: