| Conditions | 3 |
| Paths | 4 |
| Total Lines | 11 |
| Code Lines | 5 |
| Lines | 0 |
| Ratio | 0 % |
| Tests | 0 |
| CRAP Score | 12 |
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| 1 | <?php |
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| 15 | protected function decodeHttpResponse($content, $unwrap = true) |
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| 16 | { |
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| 17 | if ($content instanceof TestResponse) { |
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| 18 | $content = $content->content(); |
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| 19 | } |
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| 20 | |||
| 21 | if ($unwrap) { |
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| 22 | return json_decode($content, true)['data'] ?? json_decode($content, true); |
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| 23 | } |
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| 24 | |||
| 25 | return json_decode($content, true); |
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| 26 | } |
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| 37 |
Let?s assume that you have a directory layout like this:
. |-- OtherDir | |-- Bar.php | `-- Foo.php `-- SomeDir `-- Foo.phpand let?s assume the following content of
Bar.php:If both files
OtherDir/Foo.phpandSomeDir/Foo.phpare loaded in the same runtime, you will see a PHP error such as the following:PHP Fatal error: Cannot use SomeDir\Foo as Foo because the name is already in use in OtherDir/Foo.phpHowever, as
OtherDir/Foo.phpdoes not necessarily have to be loaded and the error is only triggered if it is loaded beforeOtherDir/Bar.php, this problem might go unnoticed for a while. In order to prevent this error from surfacing, you must import the namespace with a different alias: