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# -*- coding: utf-8 -*- |
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# Copyright 2014-2018 by Christopher C. Little. |
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# This file is part of Abydos. |
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# |
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# Abydos is free software: you can redistribute it and/or modify |
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# it under the terms of the GNU General Public License as published by |
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# the Free Software Foundation, either version 3 of the License, or |
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# (at your option) any later version. |
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# |
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# Abydos is distributed in the hope that it will be useful, |
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# but WITHOUT ANY WARRANTY; without even the implied warranty of |
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the |
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# GNU General Public License for more details. |
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# |
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# You should have received a copy of the GNU General Public License |
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# along with Abydos. If not, see <http://www.gnu.org/licenses/>. |
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"""abydos.phonetic._caverphone. |
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Caverphone phonetic algorithm |
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""" |
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from __future__ import ( |
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absolute_import, |
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division, |
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print_function, |
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unicode_literals, |
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) |
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from ._phonetic import Phonetic |
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__all__ = ['Caverphone', 'caverphone'] |
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class Caverphone(Phonetic): |
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"""Caverphone. |
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A description of version 1 of the algorithm can be found in |
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:cite:`Hood:2002`. |
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A description of version 2 of the algorithm can be found in |
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:cite:`Hood:2004`. |
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""" |
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def encode(self, word, version=2): |
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"""Return the Caverphone code for a word. |
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Args: |
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word (str): The word to transform |
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version (int): The version of Caverphone to employ for encoding |
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(defaults to 2) |
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Returns: |
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str: The Caverphone value |
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Examples: |
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>>> pe = Caverphone() |
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>>> pe.encode('Christopher') |
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'KRSTFA1111' |
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>>> pe.encode('Niall') |
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'NA11111111' |
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>>> pe.encode('Smith') |
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'SMT1111111' |
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>>> pe.encode('Schmidt') |
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'SKMT111111' |
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>>> pe.encode('Christopher', 1) |
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'KRSTF1' |
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>>> pe.encode('Niall', 1) |
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'N11111' |
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>>> pe.encode('Smith', 1) |
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'SMT111' |
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>>> pe.encode('Schmidt', 1) |
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'SKMT11' |
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""" |
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word = word.lower() |
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word = ''.join(c for c in word if c in self._lc_set) |
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def _squeeze_replace(word, char): |
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"""Convert strings of char in word to one instance. |
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Args: |
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word (str): The partially converted word |
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char (str): A character to 'squeeze' |
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Returns: |
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str: The word with instances of char squeezed down to one |
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""" |
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while char * 2 in word: |
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word = word.replace(char * 2, char) |
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return word.replace(char, char.upper()) |
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# the main replacement algorithm |
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if version != 1 and word[-1:] == 'e': |
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word = word[:-1] |
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if word: |
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if word[:5] == 'cough': |
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word = 'cou2f' + word[5:] |
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if word[:5] == 'rough': |
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word = 'rou2f' + word[5:] |
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if word[:5] == 'tough': |
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word = 'tou2f' + word[5:] |
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if word[:6] == 'enough': |
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word = 'enou2f' + word[6:] |
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if version != 1 and word[:6] == 'trough': |
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word = 'trou2f' + word[6:] |
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if word[:2] == 'gn': |
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word = '2n' + word[2:] |
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if word[-2:] == 'mb': |
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word = word[:-1] + '2' |
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for src, tar in ( |
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('cq', '2q'), |
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('ci', 'si'), |
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('ce', 'se'), |
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('cy', 'sy'), |
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('tch', '2ch'), |
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('c', 'k'), |
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('q', 'k'), |
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('x', 'k'), |
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('v', 'f'), |
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('dg', '2g'), |
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('tio', 'sio'), |
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('tia', 'sia'), |
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('d', 't'), |
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('ph', 'fh'), |
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('b', 'p'), |
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('sh', 's2'), |
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('z', 's'), |
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): |
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word = word.replace(src, tar) |
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if word[0] in self._lc_v_set: |
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word = 'A' + word[1:] |
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for vowel in 'aeiou': |
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word = word.replace(vowel, '3') |
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if version != 1: |
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word = word.replace('j', 'y') |
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if word[:2] == 'y3': |
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word = 'Y3' + word[2:] |
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if word[:1] == 'y': |
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word = 'A' + word[1:] |
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word = word.replace('y', '3') |
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for src, tar in (('3gh3', '3kh3'), ('gh', '22'), ('g', 'k')): |
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word = word.replace(src, tar) |
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for char in 'stpkfmn': |
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word = _squeeze_replace(word, char) |
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word = word.replace('w3', 'W3') |
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if version == 1: |
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word = word.replace('wy', 'Wy') |
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word = word.replace('wh3', 'Wh3') |
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if version == 1: |
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word = word.replace('why', 'Why') |
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if version != 1 and word[-1:] == 'w': |
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word = word[:-1] + '3' |
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word = word.replace('w', '2') |
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if word[:1] == 'h': |
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word = 'A' + word[1:] |
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word = word.replace('h', '2') |
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word = word.replace('r3', 'R3') |
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if version == 1: |
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word = word.replace('ry', 'Ry') |
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if version != 1 and word[-1:] == 'r': |
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word = word[:-1] + '3' |
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word = word.replace('r', '2') |
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word = word.replace('l3', 'L3') |
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if version == 1: |
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word = word.replace('ly', 'Ly') |
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if version != 1 and word[-1:] == 'l': |
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word = word[:-1] + '3' |
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word = word.replace('l', '2') |
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if version == 1: |
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word = word.replace('j', 'y') |
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word = word.replace('y3', 'Y3') |
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word = word.replace('y', '2') |
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word = word.replace('2', '') |
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if version != 1 and word[-1:] == '3': |
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word = word[:-1] + 'A' |
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word = word.replace('3', '') |
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# pad with 1s, then extract the necessary length of code |
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word += '1' * 10 |
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if version != 1: |
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word = word[:10] |
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else: |
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word = word[:6] |
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return word |
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def caverphone(word, version=2): |
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"""Return the Caverphone code for a word. |
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This is a wrapper for :py:meth:`Caverphone.encode`. |
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Args: |
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word (str): The word to transform |
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version (int): The version of Caverphone to employ for encoding |
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(defaults to 2) |
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Returns: |
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str: The Caverphone value |
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Examples: |
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>>> caverphone('Christopher') |
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'KRSTFA1111' |
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>>> caverphone('Niall') |
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'NA11111111' |
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>>> caverphone('Smith') |
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'SMT1111111' |
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>>> caverphone('Schmidt') |
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'SKMT111111' |
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>>> caverphone('Christopher', 1) |
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'KRSTF1' |
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>>> caverphone('Niall', 1) |
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'N11111' |
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>>> caverphone('Smith', 1) |
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'SMT111' |
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>>> caverphone('Schmidt', 1) |
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'SKMT11' |
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""" |
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return Caverphone().encode(word, version) |
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if __name__ == '__main__': |
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import doctest |
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doctest.testmod() |
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