abydos.phonetic._haase.Haase.encode()

Complexity

Conditions

39

Size

Total Lines	176
Code Lines	107

Duplication

Lines	47
Ratio	26.7 %

Code Coverage

Tests	97
CRAP Score	39

Importance

Changes

0

# -*- coding: utf-8 -*-
    def encode(self, word, primary_only=False):

Parameters differ from overridden 'encode' method

        """Return the Haase Phonetik (numeric output) code for a word.

        While the output code is numeric, it is nevertheless a str.

        Args:
            word (str): The word to transform
            primary_only (bool): If True, only the primary code is returned

        Returns:
            tuple: The Haase Phonetik value as a numeric string

        Examples:
            >>> pe = Haase()
            >>> pe.encode('Joachim')
            ('9496',)
            >>> pe.encode('Christoph')
            ('4798293', '8798293')
            >>> pe.encode('Jörg')
            ('974',)
            >>> pe.encode('Smith')
            ('8692',)
            >>> pe.encode('Schmidt')
            ('8692', '4692')

        """

        def _after(word, pos, letters):
            """Return True if word[pos] follows one of the supplied letters.

            Args:
                word (str): Word to modify
                pos (int): Position to examine
                letters (set): Letters to check for

            Returns:
                bool: True if word[pos] follows one of letters

            """
            if pos > 0 and word[pos - 1] in letters:
                return True
            return False

        def _before(word, pos, letters):
            """Return True if word[pos] precedes one of the supplied letters.

            Args:
                word (str): Word to modify
                pos (int): Position to examine
                letters (set): Letters to check for

            Returns:
                bool: True if word[pos] precedes one of letters

            """
            if pos + 1 < len(word) and word[pos + 1] in letters:
                return True
            return False

        word = unicode_normalize('NFKD', text_type(word.upper()))
        word = word.replace('ß', 'SS')

        word = word.replace('Ä', 'AE')
        word = word.replace('Ö', 'OE')
        word = word.replace('Ü', 'UE')
        word = ''.join(c for c in word if c in self._uc_set)

        variants = []
        if primary_only:
            variants = [word]
        else:
            pos = 0
            if word[:2] == 'CH':
                variants.append(('CH', 'SCH'))
                pos += 2
            len_3_vars = {
                'OWN': 'AUN',
                'WSK': 'RSK',
                'SCH': 'CH',
                'GLI': 'LI',
                'AUX': 'O',
                'EUX': 'O',
            }
            while pos < len(word):
                if word[pos : pos + 4] == 'ILLE':
                    variants.append(('ILLE', 'I'))
                    pos += 4
                elif word[pos : pos + 3] in len_3_vars:
                    variants.append(
                        (word[pos : pos + 3], len_3_vars[word[pos : pos + 3]])
                    )
                    pos += 3
                elif word[pos : pos + 2] == 'RB':
                    variants.append(('RB', 'RW'))
                    pos += 2
                elif len(word[pos:]) == 3 and word[pos:] == 'EAU':
                    variants.append(('EAU', 'O'))
                    pos += 3
                elif len(word[pos:]) == 1 and word[pos:] in {'A', 'O'}:
                    if word[pos:] == 'O':
                        variants.append(('O', 'OW'))
                    else:
                        variants.append(('A', 'AR'))
                    pos += 1
                else:
                    variants.append((word[pos],))
                    pos += 1

            variants = [''.join(letters) for letters in product(*variants)]

        def _haase_code(word):
            sdx = ''
            for i in range(len(word)):

Consider using enumerate instead of iterating with range and len

                if word[i] in self._uc_v_set:

This code seems to be duplicated in your project.

                    sdx += '9'
                elif word[i] == 'B':
                    sdx += '1'
                elif word[i] == 'P':
                    if _before(word, i, {'H'}):
                        sdx += '3'
                    else:
                        sdx += '1'
                elif word[i] in {'D', 'T'}:
                    if _before(word, i, {'C', 'S', 'Z'}):
                        sdx += '8'
                    else:
                        sdx += '2'
                elif word[i] in {'F', 'V', 'W'}:
                    sdx += '3'
                elif word[i] in {'G', 'K', 'Q'}:
                    sdx += '4'
                elif word[i] == 'C':
                    if _after(word, i, {'S', 'Z'}):
                        sdx += '8'
                    elif i == 0:
                        if _before(
                            word,

Wrong hanging indentation before block (add 4 spaces).

                            i,

Wrong hanging indentation before block (add 4 spaces).

                            {'A', 'H', 'K', 'L', 'O', 'Q', 'R', 'U', 'X'},

Wrong hanging indentation before block (add 4 spaces).

                        ):
                            sdx += '4'
                        else:
                            sdx += '8'
                    elif _before(word, i, {'A', 'H', 'K', 'O', 'Q', 'U', 'X'}):
                        sdx += '4'
                    else:
                        sdx += '8'
                elif word[i] == 'X':
                    if _after(word, i, {'C', 'K', 'Q'}):
                        sdx += '8'
                    else:
                        sdx += '48'
                elif word[i] == 'L':
                    sdx += '5'
                elif word[i] in {'M', 'N'}:
                    sdx += '6'
                elif word[i] == 'R':
                    sdx += '7'
                elif word[i] in {'S', 'Z'}:
                    sdx += '8'

            sdx = self._delete_consecutive_repeats(sdx)

            return sdx

        encoded = tuple(_haase_code(word) for word in variants)
        if len(encoded) > 1:
            encoded_set = set()
            encoded_single = []
            for code in encoded:
                if code not in encoded_set:
                    encoded_set.add(code)
                    encoded_single.append(code)
            return tuple(encoded_single)

        return encoded