| Conditions | 2 | 
| Paths | 2 | 
| Total Lines | 10 | 
| Code Lines | 5 | 
| Lines | 0 | 
| Ratio | 0 % | 
| Changes | 2 | ||
| Bugs | 0 | Features | 0 | 
| 1 | <?php | ||
| 22 | public function getRules(ValidatorInterface $validator, ElementInterface $element = null) | ||
| 23 |     { | ||
| 24 | $token = $validator->getToken(); | ||
|  | |||
| 25 | |||
| 26 |         if (strpos($element->getName(), "[") !== false) { | ||
| 27 |             $token = preg_replace('#\[[^\]]+\]$#i', "[" . $token . "]", $element->getName()); | ||
| 28 | } | ||
| 29 | |||
| 30 |         return array('equalTo' => '[name="' . $token . '"]'); | ||
| 31 | } | ||
| 32 | |||
| 52 | 
Let’s take a look at an example:
In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.
Available Fixes
Change the type-hint for the parameter:
Add an additional type-check:
Add the method to the interface: