The variable $params does not exist. Did you forget to declare it?
This check marks access to variables or properties that have not been declared yet. While PHP
has no explicit notion of declaring a variable, accessing it before a value is assigned
to it is most likely a bug.
The variable $value does not seem to be defined for all execution paths leading up to this point.
If you define a variable conditionally, it can happen that it is not defined
for all execution paths.
Let’s take a look at an example:
functionmyFunction($a){switch($a){case'foo':$x=1;break;case'bar':$x=2;break;}// $x is potentially undefined here.echo$x;}
In the above example, the variable $x is defined if you pass “foo” or “bar”
as argument for $a. However, since the switch statement has no default
case statement, if you pass any other value, the variable $x would be undefined.
Available Fixes
Check for existence of the variable explicitly:
functionmyFunction($a){switch($a){case'foo':$x=1;break;case'bar':$x=2;break;}if(isset($x)){// Make sure it's always set.echo$x;}}
Define a default value for the variable:
functionmyFunction($a){$x='';// Set a default which gets overridden for certain paths.switch($a){case'foo':$x=1;break;case'bar':$x=2;break;}echo$x;}
Add a value for the missing path:
functionmyFunction($a){switch($a){case'foo':$x=1;break;case'bar':$x=2;break;// We add support for the missing case.default:$x='';break;}echo$x;}
basis-company /
framework.php
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It seems like the type of the argument is not accepted by the function/method which you are calling.
In some cases, in particular if PHP’s automatic type-juggling kicks in this might be fine. In other cases, however this might be a bug.
We suggest to add an explicit type cast like in the following example: