Jquery.js ➔ ... ➔ ga.setDocument   F
last analyzed

Complexity

Conditions 13
Paths 0

Size

Total Lines 1

Duplication

Lines 0
Ratio 0 %

Importance

Changes 1
Bugs 0 Features 0
Metric Value
cc 13
c 1
b 0
f 0
nc 0
nop 1
dl 0
loc 1
rs 2

How to fix   Complexity   

Complexity

Complex classes like Jquery.js ➔ ... ➔ ga.setDocument often do a lot of different things. To break such a class down, we need to identify a cohesive component within that class. A common approach to find such a component is to look for fields/methods that share the same prefixes, or suffixes.

Once you have determined the fields that belong together, you can apply the Extract Class refactoring. If the component makes sense as a sub-class, Extract Subclass is also a candidate, and is often faster.

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0 ignored issues
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Unused Code introduced by
The assignment to b seems to be never used. If you intend to free memory here, this is not necessary since the variable leaves the scope anyway.
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Bug introduced by
The variable b is changed as part of the for loop for example by b++ on line 2. Only the value of the last iteration will be visible in this function if it is called after the loop.
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Comprehensibility Best Practice introduced by
You seem to be aliasing the built-in name eval as c. This makes your code very difficult to follow, consider using the built-in name directly.
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Bug introduced by
The variable f seems to not be initialized for all possible execution paths.
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Complexity Best Practice introduced by
There is no return statement if "undefined" != typeof b.getElementById && p is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

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Best Practice introduced by
There is no return statement in this branch, but you do return something in other branches. Did you maybe miss it? If you do not want to return anything, consider adding return undefined; explicitly.
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Bug introduced by
The variable g is changed as part of the for loop for example by g++ on line 2. Only the value of the last iteration will be visible in this function if it is called after the loop.
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Bug introduced by
The variable m seems to not be initialized for all possible execution paths.
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Bug introduced by
The variable k does not seem to be initialized in case j = o.0 = o.0.slice(0), ... && d.relative.j.1.type on line 2 is true. Are you sure this can never be the case?
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Coding Style introduced by
Consider using undefined instead of void(0). It is equivalent and more straightforward to read.
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Bug introduced by
The variable n does not seem to be initialized in case s && j = b.u || b.u = {}.a && j.0 === w on line 2 is false. Are you sure this can never be the case?
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Unused Code introduced by
The assignment to variable c seems to be never used. Consider removing it.
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Comprehensibility introduced by
Usage of the sequence operator is discouraged, since it may lead to obfuscated code.

The sequence or comma operator allows the inclusion of multiple expressions where only is permitted. The result of the sequence is the value of the last expression.

This operator is most often used in for statements.

Used in another places it can make code hard to read, especially when people do not realize it even exists as a seperate operator.

This check looks for usage of the sequence operator in locations where it is not necessary and could be replaced by a series of expressions or statements.

var a,b,c;

a = 1, b = 1,  c= 3;

could just as well be written as:

var a,b,c;

a = 1;
b = 1;
c = 3;

To learn more about the sequence operator, please refer to the MDN.

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Coding Style Best Practice introduced by
Curly braces around statements make for more readable code and help prevent bugs when you add further statements.

Consider adding curly braces around all statements when they are executed conditionally. This is optional if there is only one statement, but leaving them out can lead to unexpected behaviour if another statement is added later.

Consider:

if (a > 0)
    b = 42;

If you or someone else later decides to put another statement in, only the first statement will be executed.

if (a > 0)
    console.log("a > 0");
    b = 42;

In this case the statement b = 42 will always be executed, while the logging statement will be executed conditionally.

if (a > 0) {
    console.log("a > 0");
    b = 42;
}

ensures that the proper code will be executed conditionally no matter how many statements are added or removed.

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introduced by
You have used a bitwise operator & in a condition. Did you maybe want to use the logical operator &&
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Unused Code introduced by
The loop variable c is initialized by the loop but not used in the test. Consider using another type of loop if this is the intended behavior.
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Bug introduced by
The variable c seems to not be initialized for all possible execution paths. Are you sure inArray handles undefined variables?
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Bug introduced by
The variable k does not seem to be initialized in case e > 1 on line 2 is false. Are you sure the function resolveWith handles undefined variables?
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Bug introduced by
The variable g seems to not be initialized for all possible execution paths.
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introduced by
The while loop does not have a body. Maybe you have misplaced a semicolon. If you do wish to have a loop without a body, use an empty body {}.
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Coding Style Best Practice introduced by
By convention, constructors like qa should be capitalized.
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Unused Code introduced by
The variable b seems to be never used. Consider removing it.
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Bug introduced by
The variable p seems to not be initialized for all possible execution paths.
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Complexity Best Practice introduced by
There is no return statement if q is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

Loading history...
3
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a,b=0,c=n.timers;for(La=n.now();b<c.length;b++)a=c[b],a()||c[b]!==a||c.splice(b--,1);c.length||n.fx.stop(),La=void 0},n.fx.timer=function(a){n.timers.push(a),a()?n.fx.start():n.timers.pop()},n.fx.interval=13,n.fx.start=function(){Ma||(Ma=setInterval(n.fx.tick,n.fx.interval))},n.fx.stop=function(){clearInterval(Ma),Ma=null},n.fx.speeds={slow:600,fast:200,_default:400},n.fn.delay=function(a,b){return a=n.fx?n.fx.speeds[a]||a:a,b=b||"fx",this.queue(b,function(b,c){var d=setTimeout(b,a);c.stop=function(){clearTimeout(d)}})},function(){var a=l.createElement("input"),b=l.createElement("select"),c=b.appendChild(l.createElement("option"));a.type="checkbox",k.checkOn=""!==a.value,k.optSelected=c.selected,b.disabled=!0,k.optDisabled=!c.disabled,a=l.createElement("input"),a.value="t",a.type="radio",k.radioValue="t"===a.value}();var Ya,Za,$a=n.expr.attrHandle;n.fn.extend({attr:function(a,b){return J(this,n.attr,a,b,arguments.length>1)},removeAttr:function(a){return this.each(function(){n.removeAttr(this,a)})}}),n.extend({attr:function(a,b,c){var d,e,f=a.nodeType;if(a&&3!==f&&8!==f&&2!==f)return typeof a.getAttribute===U?n.prop(a,b,c):(1===f&&n.isXMLDoc(a)||(b=b.toLowerCase(),d=n.attrHooks[b]||(n.expr.match.bool.test(b)?Za:Ya)),
0 ignored issues
show
Bug introduced by
The variable b seems to not be initialized for all possible execution paths.
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Complexity Best Practice introduced by
There is no return statement if a && 3 !== f && 8 !== f && 2 !== f is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

Loading history...
Bug introduced by
The variable d seems to not be initialized for all possible execution paths.
Loading history...
Complexity Best Practice introduced by
There is no return statement if c = P(f, d, void(0)), void(0) !== c is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

Loading history...
Bug introduced by
The variable e seems to not be initialized for all possible execution paths.
Loading history...
Complexity Best Practice introduced by
There is no return statement if a && 3 !== a.nodeType &&...= a.nodeType && a.style is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

Loading history...
Bug introduced by
The variable c seems to not be initialized for all possible execution paths.
Loading history...
Complexity Best Practice introduced by
There is no return statement if b is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

Loading history...
Bug introduced by
The variable e does not seem to be initialized in case this.length && e = M.get....get(f, "hasDataAttrs") on line 3 is false. Are you sure this can never be the case?
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introduced by
You have used a bitwise operator & in a condition. Did you maybe want to use the logical operator &&
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Bug introduced by
The variable j seems to not be initialized for all possible execution paths.
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Comprehensibility introduced by
Usage of the sequence operator is discouraged, since it may lead to obfuscated code.

The sequence or comma operator allows the inclusion of multiple expressions where only is permitted. The result of the sequence is the value of the last expression.

This operator is most often used in for statements.

Used in another places it can make code hard to read, especially when people do not realize it even exists as a seperate operator.

This check looks for usage of the sequence operator in locations where it is not necessary and could be replaced by a series of expressions or statements.

var a,b,c;

a = 1, b = 1,  c= 3;

could just as well be written as:

var a,b,c;

a = 1;
b = 1;
c = 3;

To learn more about the sequence operator, please refer to the MDN.

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Bug introduced by
The variable i does not seem to be initialized in case !e && !o.noBubble && !n.isWindow(d) on line 3 is false. Are you sure this can never be the case?
Loading history...
Complexity Best Practice introduced by
There is no return statement if i.0 = a, a.delegateTarge...ch.call(this, a) !== !1 is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

Loading history...
Bug introduced by
The variable o does not seem to be initialized in case g = h = d = d || l, 3 !=...gger.apply(d, c) !== !1 on line 3 is true. Are you sure this can never be the case?
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Unused Code introduced by
The assignment to variable h seems to be never used. Consider removing it.
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Bug introduced by
The variable Ya seems to be never initialized.
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Bug introduced by
The function g is declared conditionally. This is not supported by all runtimes. Consider moving it to root scope or using var g = function() { /* ... */ }; instead.
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Bug introduced by
The variable f seems to not be initialized for all possible execution paths. Are you sure extend handles undefined variables?
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Coding Style Best Practice introduced by
Curly braces around statements make for more readable code and help prevent bugs when you add further statements.

Consider adding curly braces around all statements when they are executed conditionally. This is optional if there is only one statement, but leaving them out can lead to unexpected behaviour if another statement is added later.

Consider:

if (a > 0)
    b = 42;

If you or someone else later decides to put another statement in, only the first statement will be executed.

if (a > 0)
    console.log("a > 0");
    b = 42;

In this case the statement b = 42 will always be executed, while the logging statement will be executed conditionally.

if (a > 0) {
    console.log("a > 0");
    b = 42;
}

ensures that the proper code will be executed conditionally no matter how many statements are added or removed.

Loading history...
Complexity Best Practice introduced by
There is no return statement if g = h = d = d || l, 3 !=...gger.apply(d, c) !== !1 is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

Loading history...
Coding Style introduced by
Consider using undefined instead of void(0). It is equivalent and more straightforward to read.
Loading history...
Coding Style Comprehensibility Best Practice introduced by
Empty catch clauses should be used with caution; consider adding a comment why this is needed.
Loading history...
Bug introduced by
The variable g seems to not be initialized for all possible execution paths.
Loading history...
Best Practice introduced by
There is no return statement in this branch, but you do return something in other branches. Did you maybe miss it? If you do not want to return anything, consider adding return undefined; explicitly.
Loading history...
4 View Code Duplication
    void 0===c?d&&"get"in d&&null!==(e=d.get(a,b))?e:(e=n.find.attr(a,b),null==e?void 0:e):null!==c?d&&"set"in d&&void 0!==(e=d.set(a,c,b))?e:(a.setAttribute(b,c+""),c):void n.removeAttr(a,b))},removeAttr:function(a,b){var c,d,e=0,f=b&&b.match(E);if(f&&1===a.nodeType)while(c=f[e++])d=n.propFix[c]||c,n.expr.match.bool.test(c)&&(a[d]=!1),a.removeAttribute(c)},attrHooks:{type:{set:function(a,b){if(!k.radioValue&&"radio"===b&&n.nodeName(a,"input")){var c=a.value;return a.setAttribute("type",b),c&&(a.value=c),b}}}}}),Za={set:function(a,b,c){return b===!1?n.removeAttr(a,c):a.setAttribute(c,c),c}},n.each(n.expr.match.bool.source.match(/\w+/g),function(a,b){var c=$a[b]||n.find.attr;$a[b]=function(a,b,d){var e,f;return d||(f=$a[b],$a[b]=e,e=null!=c(a,b,d)?b.toLowerCase():null,$a[b]=f),e}});var _a=/^(?:input|select|textarea|button)$/i;n.fn.extend({prop:function(a,b){return J(this,n.prop,a,b,arguments.length>1)},removeProp:function(a){return this.each(function(){delete 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0})}),n.each({Height:"height",Width:"width"},function(a,b){n.each({padding:"inner"+a,content:b,"":"outer"+a},function(c,d){n.fn[d]=function(d,e){var f=arguments.length&&(c||"boolean"!=typeof d),g=c||(d===!0||e===!0?"margin":"border");return J(this,function(b,c,d){var e;return n.isWindow(b)?b.document.documentElement["client"+a]:9===b.nodeType?(e=b.documentElement,Math.max(b.body["scroll"+a],e["scroll"+a],b.body["offset"+a],e["offset"+a],e["client"+a])):void 0===d?n.css(b,c,g):n.style(b,c,d,g)},b,f?d:void 0,f,null)}})}),n.fn.size=function(){return this.length},n.fn.andSelf=n.fn.addBack,"function"==typeof define&&define.amd&&define("jquery",[],function(){return n});var Kb=a.jQuery,Lb=a.$;return n.noConflict=function(b){return a.$===n&&(a.$=Lb),b&&a.jQuery===n&&(a.jQuery=Kb),n},typeof b===U&&(a.jQuery=a.$=n),n});
0 ignored issues
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Bug introduced by
The variable e seems to be never initialized.
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Comprehensibility introduced by
Usage of the sequence operator is discouraged, since it may lead to obfuscated code.

The sequence or comma operator allows the inclusion of multiple expressions where only is permitted. The result of the sequence is the value of the last expression.

This operator is most often used in for statements.

Used in another places it can make code hard to read, especially when people do not realize it even exists as a seperate operator.

This check looks for usage of the sequence operator in locations where it is not necessary and could be replaced by a series of expressions or statements.

var a,b,c;

a = 1, b = 1,  c= 3;

could just as well be written as:

var a,b,c;

a = 1;
b = 1;
c = 3;

To learn more about the sequence operator, please refer to the MDN.

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Complexity Best Practice introduced by
There is no return statement if f is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

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Complexity Best Practice introduced by
There is no return statement if a.crossDomain is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

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Bug introduced by
The variable b does not seem to be initialized in case 2 === t on line 4 is false. Are you sure this can never be the case?
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Bug introduced by
The variable u seems to not be initialized for all possible execution paths. Are you sure ub handles undefined variables?
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Bug introduced by
The variable define seems to be never declared. If this is a global, consider adding a /** global: define */ comment.

This checks looks for references to variables that have not been declared. This is most likey a typographical error or a variable has been renamed.

To learn more about declaring variables in Javascript, see the MDN.

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Bug introduced by
The variable s seems to not be initialized for all possible execution paths.
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Bug introduced by
The variable c does not seem to be initialized in case e on line 4 is true. Are you sure this can never be the case?
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Bug introduced by
The variable g seems to not be initialized for all possible execution paths.
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Best Practice introduced by
There is no return statement in this branch, but you do return something in other branches. Did you maybe miss it? If you do not want to return anything, consider adding return undefined; explicitly.
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Coding Style Best Practice introduced by
Curly braces around statements make for more readable code and help prevent bugs when you add further statements.

Consider adding curly braces around all statements when they are executed conditionally. This is optional if there is only one statement, but leaving them out can lead to unexpected behaviour if another statement is added later.

Consider:

if (a > 0)
    b = 42;

If you or someone else later decides to put another statement in, only the first statement will be executed.

if (a > 0)
    console.log("a > 0");
    b = 42;

In this case the statement b = 42 will always be executed, while the logging statement will be executed conditionally.

if (a > 0) {
    console.log("a > 0");
    b = 42;
}

ensures that the proper code will be executed conditionally no matter how many statements are added or removed.

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Complexity Best Practice introduced by
There is no return statement if !k.radioValue && "radio"... n.nodeName(a, "input") is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

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Complexity Best Practice introduced by
There is no return statement if e is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

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Bug introduced by
The variable d seems to not be initialized for all possible execution paths.
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Complexity Best Practice introduced by
There is no return statement if a && 3 !== g && 8 !== g && 2 !== g is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

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Coding Style Comprehensibility Best Practice introduced by
Empty catch clauses should be used with caution; consider adding a comment why this is needed.
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Complexity Best Practice introduced by
There is no return statement if this.0 is false. Are you sure this is correct? If so, consider adding return; explicitly.

This check looks for functions where a return statement is found in some execution paths, but not in all.

Consider this little piece of code

function isBig(a) {
    if (a > 5000) {
        return "yes";
    }
}

console.log(isBig(5001)); //returns yes
console.log(isBig(42)); //returns undefined

The function isBig will only return a specific value when its parameter is bigger than 5000. In any other case, it will implicitly return undefined.

This behaviour may not be what you had intended. In any case, you can add a return undefined to the other execution path to make the return value explicit.

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Bug introduced by
The variable d does not seem to be initialized in case a && 3 !== g && 8 !== g && 2 !== g on line 4 is true. Are you sure this can never be the case?
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Bug introduced by
The variable DOMParser seems to be never declared. If this is a global, consider adding a /** global: DOMParser */ comment.

This checks looks for references to variables that have not been declared. This is most likey a typographical error or a variable has been renamed.

To learn more about declaring variables in Javascript, see the MDN.

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Bug introduced by
The variable e seems to not be initialized for all possible execution paths.
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Complexity introduced by
A for in loop automatically includes the property of any prototype object, consider checking the key using hasOwnProperty.

When iterating over the keys of an object, this includes not only the keys of the object, but also keys contained in the prototype of that object. It is generally a best practice to check for these keys specifically:

var someObject;
for (var key in someObject) {
    if ( ! someObject.hasOwnProperty(key)) {
        continue; // Skip keys from the prototype.
    }

    doSomethingWith(key);
}
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Bug introduced by
The variable XMLHttpRequest seems to be never declared. If this is a global, consider adding a /** global: XMLHttpRequest */ comment.

This checks looks for references to variables that have not been declared. This is most likey a typographical error or a variable has been renamed.

To learn more about declaring variables in Javascript, see the MDN.

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Bug introduced by
The variable e does not seem to be initialized in case a && 3 !== f && 8 !== f && 2 !== f on line 3 is true. Are you sure this can never be the case?
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Bug introduced by
The variable r seems to not be initialized for all possible execution paths.
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Coding Style introduced by
Consider using undefined instead of void(0). It is equivalent and more straightforward to read.
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Duplication introduced by
This code seems to be duplicated in your project.
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Duplication introduced by
This code seems to be duplicated in your project.
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