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VirtualBusinessPageReferenceBuilder   A

Complexity

Total Complexity 2

Size/Duplication

Total Lines 13
Duplicated Lines 0 %

Coupling/Cohesion

Components 0
Dependencies 2

Importance

Changes 1
Bugs 0 Features 0
Metric Value
wmc 2
lcom 0
cbo 2
dl 0
loc 13
rs 10
c 1
b 0
f 0

1 Method

Rating   Name   Duplication   Size   Complexity  
A buildReference() 0 10 2
1
<?php
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namespace Victoire\Bundle\BusinessPageBundle\Builder;
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use Doctrine\ORM\EntityManager;
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use Metadata\ClassMetadata;
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use Victoire\Bundle\CoreBundle\Entity\View;
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/**
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 * VirtualBusinessPageReferenceBuilder.
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 */
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class VirtualBusinessPageReferenceBuilder extends BusinessPageReferenceBuilder
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{
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    public function buildReference(View $businessPage, EntityManager $em)
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    {
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        $businessPageReference = null;
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        $businessEntityMetadata = new ClassMetadata(get_class($businessPage->getBusinessEntity()));
0 ignored issues
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Bug introduced by
It seems like you code against a specific sub-type and not the parent class Victoire\Bundle\CoreBundle\Entity\View as the method getBusinessEntity() does only exist in the following sub-classes of Victoire\Bundle\CoreBundle\Entity\View: Victoire\Bundle\Business...dle\Entity\BusinessPage, Victoire\Bundle\Business...ity\VirtualBusinessPage. Maybe you want to instanceof check for one of these explicitly?

Let’s take a look at an example:

abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the parent class:

    abstract class User
    {
        /** @return string */
        abstract public function getPassword();
    
        /** @return string */
        abstract public function getDisplayName();
    }
    
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18
        if ($businessEntityMetadata->name !== 'Victoire\Bundle\BlogBundle\Entity\Article') {
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            $businessPageReference = parent::buildReference($businessPage, $em);
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        }
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        return $businessPageReference;
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    }
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}
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