SerhiiCho /
timeago
| Conditions | 14 |
| Total Lines | 23 |
| Code Lines | 19 |
| Lines | 0 |
| Ratio | 0 % |
| Changes | 0 | ||
Complex classes like timeago.getRules often do a lot of different things. To break such a class down, we need to identify a cohesive component within that class. A common approach to find such a component is to look for fields/methods that share the same prefixes, or suffixes.
Once you have determined the fields that belong together, you can apply the Extract Class refactoring. If the component makes sense as a sub-class, Extract Subclass is also a candidate, and is often faster.
| 1 | package timeago |
||
| 9 | One bool |
||
| 10 | Two bool |
||
| 11 | Few bool |
||
| 12 | Many bool |
||
| 13 | Other bool |
||
| 14 | } |
||
| 15 | |||
| 16 | var grammarRules = func(num int) map[string]*Rule { |
||
| 17 | end := num % 10 |
||
| 18 | |||
| 19 | return map[string]*Rule{ |
||
| 20 | "en,nl,de": { |
||
| 21 | Zero: num == 0, |
||
| 22 | One: num == 1, |
||
| 23 | Two: num == 2, |
||
| 24 | Few: num > 1, |
||
| 25 | Many: num > 1, |
||
| 26 | }, |
||
| 27 | "ru,uk": { |
||
| 28 | Zero: num == 0, |
||
| 29 | One: num == 1 || (num > 20 && end == 1), |
||
| 30 | Two: num == 2, |
||
| 31 | Few: end == 2 || end == 3 || end == 4, |
||
| 32 | Many: (num >= 5 && num <= 20) || end == 0 || (end >= 5 && end <= 9), |
||
| 52 |
