| Conditions | 12 | 
| Total Lines | 43 | 
| Code Lines | 35 | 
| Lines | 0 | 
| Ratio | 0 % | 
| Changes | 0 | ||
Complex classes like timeago.getRules often do a lot of different things. To break such a class down, we need to identify a cohesive component within that class. A common approach to find such a component is to look for fields/methods that share the same prefixes, or suffixes.
Once you have determined the fields that belong together, you can apply the Extract Class refactoring. If the component makes sense as a sub-class, Extract Subclass is also a candidate, and is often faster.
| 1 | package timeago  | 
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| 12 | func getRules(num int) map[string]rule { | 
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| 13 | lastDigit := num % 10  | 
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| 14 | // lastTwoDigits := num % 100  | 
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| 15 | |||
| 16 | 	return map[string]rule{ | 
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| 17 | 		"en": { | 
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| 18 | Zero: num == 0,  | 
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| 19 | One: num == 1,  | 
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| 20 | Few: num > 1,  | 
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| 21 | Two: num == 2,  | 
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| 22 | Many: num > 1,  | 
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| 23 | Other: num > 1,  | 
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| 24 | },  | 
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| 25 | 		"ru": { | 
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| 26 | // Zero: num == 0,  | 
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| 27 | One: lastDigit == 1,  | 
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| 28 | // Two: num == 2,  | 
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| 29 | Few: lastDigit == 2 || lastDigit == 3 || lastDigit == 4,  | 
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| 30 | Many: (num >= 5 && num <= 20) || lastDigit == 0 || (lastDigit >= 5 && lastDigit <= 9),  | 
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| 31 | },  | 
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| 32 | 		"uk": { | 
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| 33 | Zero: num == 0,  | 
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| 34 | One: lastDigit == 1,  | 
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| 35 | Two: num == 2,  | 
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| 36 | Few: num == 2,  | 
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| 37 | Many: lastDigit >= 2 && lastDigit < 5,  | 
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| 38 | Other: (num >= 5 && num <= 20) || lastDigit == 0 || (lastDigit >= 5 && lastDigit <= 9),  | 
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| 39 | },  | 
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| 40 | 		"nl": { | 
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| 41 | Zero: num == 0,  | 
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| 42 | One: num == 1,  | 
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| 43 | Few: num > 1,  | 
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| 44 | Two: num == 2,  | 
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| 45 | Many: num > 1,  | 
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| 46 | Other: num > 1,  | 
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| 47 | },  | 
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| 48 | 		"de": { | 
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| 49 | Zero: num == 0,  | 
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| 50 | One: num == 1,  | 
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| 51 | Few: num > 1,  | 
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| 52 | Two: num == 2,  | 
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| 53 | Many: num > 1,  | 
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| 54 | Other: num > 1,  | 
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| 55 | },  | 
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| 58 |