JsonLdResourceNodeSerializer   A
last analyzed

Complexity

Total Complexity 2

Size/Duplication

Total Lines 16
Duplicated Lines 0 %

Coupling/Cohesion

Components 0
Dependencies 1

Test Coverage

Coverage 100%

Importance

Changes 0
Metric Value
wmc 2
lcom 0
cbo 1
dl 0
loc 16
c 0
b 0
f 0
ccs 6
cts 6
cp 1
rs 10

2 Methods

Rating   Name   Duplication   Size   Complexity  
A __construct() 0 3 1
A getAdditionalSerialization() 0 5 1
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<?php
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namespace PPP\DataModel\Serializers;
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use PPP\DataModel\JsonLdResourceNode;
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use PPP\DataModel\ResourceNode;
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/**
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 * @licence AGPLv3+
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 * @author Thomas Pellissier Tanon
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 */
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class JsonLdResourceNodeSerializer extends BasicResourceNodeSerializer {
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	public function __construct() {
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		parent::__construct('resource-jsonld');
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	}
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	/**
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	 * @see AbstractResourceNodeSerializer::getAdditionalSerialization
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	 * @param JsonLdResourceNode $node
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	 */
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	protected function getAdditionalSerialization(ResourceNode $node) {
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		return array(
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			'graph' => $node->getGraph()
0 ignored issues
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Bug introduced by
It seems like you code against a specific sub-type and not the parent class PPP\DataModel\ResourceNode as the method getGraph() does only exist in the following sub-classes of PPP\DataModel\ResourceNode: PPP\DataModel\JsonLdResourceNode. Maybe you want to instanceof check for one of these explicitly?

Let’s take a look at an example:

abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the parent class:

    abstract class User
    {
        /** @return string */
        abstract public function getPassword();
    
        /** @return string */
        abstract public function getDisplayName();
    }
    
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		);
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	}
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}
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