UserController::viewAction() - Code Metrics - Inspection of "Update deps" - PowerKiKi/mqueue - Measure and Improve Code Quality continuously with Scrutinizer

Completed

Push — master ( ca1336...ce2897 )

by Adrien

created 2016-08-08 10:12 UTC

UserController::viewAction() A

↳ Parent: UserController

Complexity

Conditions	3
Paths	4

Size

Total Lines	14
Code Lines	8

Duplication

Lines	14
Ratio	100 %

Code Coverage

Tests	0
CRAP Score	12

Importance

Changes	5
Bugs	0	Features	1

Metric	Value
cc	3
eloc	8
c	5
b	0
f	1
nc	4
nop	0
dl	14
loc	14
ccs	0
cts	0
cp	0
crap	12
rs	9.4285

<?php

class UserController extends Zend_Controller_Action
namespace YourVendor;

class YourClass { }
{
    public function init()
    {
        /* Initialize action controller here */
    }

    public function indexAction()
    {
        $this->view->users = \mQueue\Model\UserMapper::fetchAll();
interface SomeInterface { }
class SomeClass implements SomeInterface {
    public $a;
}

function someFunction(SomeInterface $object) {
    if ($object instanceof SomeClass) {
        $a = $object->a;
    }
}
    }

    public function newAction()

    {
        $request = $this->getRequest();
        $form = new \mQueue\Form\User();

        if ($this->getRequest()->isPost()) {
abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}
            if ($form->isValid($request->getPost())) {
                $values = $form->getValues();
                $user = \mQueue\Model\UserMapper::insertUser($values);

                \mQueue\Model\User::setCurrent($user);

                $this->_helper->FlashMessenger('Subscription complete.');

                return $this->_helper->redirector('index', 'movie');
            }
        }

        $this->view->form = $form;
interface SomeInterface { }
class SomeClass implements SomeInterface {
    public $a;
}

function someFunction(SomeInterface $object) {
    if ($object instanceof SomeClass) {
        $a = $object->a;
    }
}
    }

    public function loginAction()

    {
        $request = $this->getRequest();
        $form = new \mQueue\Form\Login();

        if ($this->getRequest()->isPost()) {
abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}
            if ($form->isValid($request->getPost())) {
                $values = $form->getValues();

                $user = \mQueue\Model\UserMapper::findEmailPassword($values['email'], $values['password']);
                if ($user) {
                    Zend_Session::rememberMe(1 * 60 * 60 * 24 * 31 * 2); // Cookie for two months

                    \mQueue\Model\User::setCurrent($user);

                    $this->_helper->FlashMessenger('Logged in.');

                    $referrer = $values['referrer'];

                    // If we have a valid referer to one page of ourselve (except login or logout), redirect to it
                    if (strpos($referrer, $this->view->serverUrl() . $this->view->baseUrl()) === 0
interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}
                            && strpos($referrer, $this->view->serverUrl() . $this->view->url(['controller' => 'user', 'action' => 'login'])) !== 0
interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}
                            && strpos($referrer, $this->view->serverUrl() . $this->view->url(['controller' => 'user', 'action' => 'logout'])) !== 0) {
interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}
                        return $this->_redirect($values['referrer']);

                    } else {
                        return $this->_helper->redirector('index', 'movie');
                    }
                } else {
                    $this->_helper->FlashMessenger(['error' => 'Login failed.']);
                }
            }
        } else {
            $form->setDefaults([
                'referrer' => $this->getRequest()->getServer('HTTP_REFERER'),
abstract class User
{
    /** @return string */
    abstract public function getPassword();
}

class MyUser extends User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}
            ]);
        }

        $this->view->form = $form;
interface SomeInterface { }
class SomeClass implements SomeInterface {
    public $a;
}

function someFunction(SomeInterface $object) {
    if ($object instanceof SomeClass) {
        $a = $object->a;
    }
}
    }

    public function logoutAction()
    {
        \mQueue\Model\User::setCurrent(null);
    }

    public function viewAction()

    {
        if ($this->getRequest()->getParam('id')) {
            $this->view->user = \mQueue\Model\UserMapper::find($this->getRequest()->getParam('id'));
interface SomeInterface { }
class SomeClass implements SomeInterface {
    public $a;
}

function someFunction(SomeInterface $object) {
    if ($object instanceof SomeClass) {
        $a = $object->a;
    }
}
        } else {
            $this->view->user = \mQueue\Model\User::getCurrent();
interface SomeInterface { }
class SomeClass implements SomeInterface {
    public $a;
}

function someFunction(SomeInterface $object) {
    if ($object instanceof SomeClass) {
        $a = $object->a;
    }
}
        }

        if (!$this->view->user) {
interface SomeInterface { }
class SomeClass implements SomeInterface {
    public $a;
}

function someFunction(SomeInterface $object) {
    if ($object instanceof SomeClass) {
        $a = $object->a;
    }
}
            throw new Exception($this->view->translate('User not found'));
interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}
        }

        $this->view->userActivity = $this->_helper->createPaginator(\mQueue\Model\StatusMapper::getActivityQuery($this->view->user));
interface SomeInterface { }
class SomeClass implements SomeInterface {
    public $a;
}

function someFunction(SomeInterface $object) {
    if ($object instanceof SomeClass) {
        $a = $object->a;
    }
}
    }
}


1			<?php
2
3			class UserController extends Zend_Controller_Action
			0 ignored issues – show Coding Style Compatibility introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report PSR1 recommends that each class must be in a namespace of at least one level to avoid collisions. You can fix this by adding a namespace to your class: namespace YourVendor; class YourClass { } When choosing a vendor namespace, try to pick something that is not too generic to avoid conflicts with other libraries. Loading history...
4			{
5	3		public function init()
6			{
7			/* Initialize action controller here */
8	3		}
9
10	1		public function indexAction()
11			{
12	1		$this->view->users = \mQueue\Model\UserMapper::fetchAll();
			1 ignored issue – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report Accessing `users` on the interface `Zend_View_Interface` suggest that you code against a concrete implementation. How about adding an `instanceof` check? If you access a property on an interface, you most likely code against a concrete implementation of the interface. Available Fixes Adding an additional type check: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeInterface $object) { if ($object instanceof SomeClass) { $a = $object->a; } } Changing the type hint: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeClass $object) { $a = $object->a; } Loading history...
13	1		}
14
15	2		public function newAction()
			0 ignored issues – show Documentation introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report The return type could not be reliably inferred; please add a `@return` annotation. Our type inference engine in quite powerful, but sometimes the code does not provide enough clues to go by. In these cases we request you to add a `@return` annotation as described here. Loading history...
16			{
17	2		$request = $this->getRequest();
18	2		$form = new \mQueue\Form\User();
19
20	2		if ($this->getRequest()->isPost()) {
			1 ignored issue – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report It seems like you code against a specific sub-type and not the parent class `Zend_Controller_Request_Abstract` as the method `isPost()` does only exist in the following sub-classes of `Zend_Controller_Request_Abstract`: `Zend_Controller_Request_Apache404`, `Zend_Controller_Request_Http`, `Zend_Controller_Request_HttpTestCase`. Maybe you want to `instanceof` check for one of these explicitly? Let’s take a look at an example: abstract class User { /** @return string / abstract public function getPassword(); } class MyUser extends User { public function getPassword() { // return something } public function getDisplayName() { // return some name. } } class AuthSystem { public function authenticate(User $user) { $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName())); // do something. } } In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break. Available Fixes Change the type-hint for the parameter: class AuthSystem { public function authenticate(MyUser $user) { / ... / } } Add an additional type-check: class AuthSystem { public function authenticate(User $user) { if ($user instanceof MyUser) { $this->logger->info(/* ... /); } // or alternatively if ( ! $user instanceof MyUser) { throw new \LogicException( '$user must be an instance of MyUser, ' .'other instances are not supported.' ); } } } Note:* PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case. Add the method to the parent class: abstract class User { /** @return string / abstract public function getPassword(); /* @return string */ abstract public function getDisplayName(); } Loading history...
21	2		if ($form->isValid($request->getPost())) {
22	2		$values = $form->getValues();
23	2		$user = \mQueue\Model\UserMapper::insertUser($values);
24
25	2		\mQueue\Model\User::setCurrent($user);
26
27	2		$this->_helper->FlashMessenger('Subscription complete.');
28
29	2		return $this->_helper->redirector('index', 'movie');
30			}
31			}
32
33	2		$this->view->form = $form;
			1 ignored issue – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report Accessing `form` on the interface `Zend_View_Interface` suggest that you code against a concrete implementation. How about adding an `instanceof` check? If you access a property on an interface, you most likely code against a concrete implementation of the interface. Available Fixes Adding an additional type check: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeInterface $object) { if ($object instanceof SomeClass) { $a = $object->a; } } Changing the type hint: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeClass $object) { $a = $object->a; } Loading history...
34	2		}
35
36	1		public function loginAction()
			0 ignored issues – show Documentation introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report The return type could not be reliably inferred; please add a `@return` annotation. Our type inference engine in quite powerful, but sometimes the code does not provide enough clues to go by. In these cases we request you to add a `@return` annotation as described here. Loading history...
37			{
38	1		$request = $this->getRequest();
39	1		$form = new \mQueue\Form\Login();
40
41	1		if ($this->getRequest()->isPost()) {
			1 ignored issue – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report It seems like you code against a specific sub-type and not the parent class `Zend_Controller_Request_Abstract` as the method `isPost()` does only exist in the following sub-classes of `Zend_Controller_Request_Abstract`: `Zend_Controller_Request_Apache404`, `Zend_Controller_Request_Http`, `Zend_Controller_Request_HttpTestCase`. Maybe you want to `instanceof` check for one of these explicitly? Let’s take a look at an example: abstract class User { /** @return string / abstract public function getPassword(); } class MyUser extends User { public function getPassword() { // return something } public function getDisplayName() { // return some name. } } class AuthSystem { public function authenticate(User $user) { $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName())); // do something. } } In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break. Available Fixes Change the type-hint for the parameter: class AuthSystem { public function authenticate(MyUser $user) { / ... / } } Add an additional type-check: class AuthSystem { public function authenticate(User $user) { if ($user instanceof MyUser) { $this->logger->info(/* ... /); } // or alternatively if ( ! $user instanceof MyUser) { throw new \LogicException( '$user must be an instance of MyUser, ' .'other instances are not supported.' ); } } } Note:* PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case. Add the method to the parent class: abstract class User { /** @return string / abstract public function getPassword(); /* @return string */ abstract public function getDisplayName(); } Loading history...
42	1		if ($form->isValid($request->getPost())) {
43	1		$values = $form->getValues();
44
45	1		$user = \mQueue\Model\UserMapper::findEmailPassword($values['email'], $values['password']);
46	1		if ($user) {
47	1		Zend_Session::rememberMe(1 * 60 * 60 * 24 * 31 * 2); // Cookie for two months
48
49	1		\mQueue\Model\User::setCurrent($user);
50
51	1		$this->_helper->FlashMessenger('Logged in.');
52
53	1		$referrer = $values['referrer'];
54
55			// If we have a valid referer to one page of ourselve (except login or logout), redirect to it
56	1		if (strpos($referrer, $this->view->serverUrl() . $this->view->baseUrl()) === 0
			2 ignored issues – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report It seems like you code against a concrete implementation and not the interface `Zend_View_Interface` as the method `serverUrl()` does only exist in the following implementations of said interface: `Zend_View`. Let’s take a look at an example: interface User { /** @return string / public function getPassword(); } class MyUser implements User { public function getPassword() { // return something } public function getDisplayName() { // return some name. } } class AuthSystem { public function authenticate(User $user) { $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName())); // do something. } } In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break. Available Fixes Change the type-hint for the parameter: class AuthSystem { public function authenticate(MyUser $user) { / ... / } } Add an additional type-check: class AuthSystem { public function authenticate(User $user) { if ($user instanceof MyUser) { $this->logger->info(/* ... /); } // or alternatively if ( ! $user instanceof MyUser) { throw new \LogicException( '$user must be an instance of MyUser, ' .'other instances are not supported.' ); } } } Note:* PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case. Add the method to the interface: interface User { /** @return string / public function getPassword(); /* @return string / public function getDisplayName(); } Loading history... Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report It seems like you code against a concrete implementation and not the interface `Zend_View_Interface` as the method `baseUrl()` does only exist in the following implementations of said interface: `Zend_View`. Let’s take a look at an example: interface User { /* @return string / public function getPassword(); } class MyUser implements User { public function getPassword() { // return something } public function getDisplayName() { // return some name. } } class AuthSystem { public function authenticate(User $user) { $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName())); // do something. } } In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break. Available Fixes Change the type-hint for the parameter: class AuthSystem { public function authenticate(MyUser $user) { / ... / } } Add an additional type-check: class AuthSystem { public function authenticate(User $user) { if ($user instanceof MyUser) { $this->logger->info(/* ... /); } // or alternatively if ( ! $user instanceof MyUser) { throw new \LogicException( '$user must be an instance of MyUser, ' .'other instances are not supported.' ); } } } Note:* PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case. Add the method to the interface: interface User { /** @return string / public function getPassword(); /* @return string */ public function getDisplayName(); } Loading history...
57	1		&& strpos($referrer, $this->view->serverUrl() . $this->view->url(['controller' => 'user', 'action' => 'login'])) !== 0
			2 ignored issues – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report It seems like you code against a concrete implementation and not the interface `Zend_View_Interface` as the method `serverUrl()` does only exist in the following implementations of said interface: `Zend_View`. Let’s take a look at an example: interface User { /** @return string / public function getPassword(); } class MyUser implements User { public function getPassword() { // return something } public function getDisplayName() { // return some name. } } class AuthSystem { public function authenticate(User $user) { $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName())); // do something. } } In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break. Available Fixes Change the type-hint for the parameter: class AuthSystem { public function authenticate(MyUser $user) { / ... / } } Add an additional type-check: class AuthSystem { public function authenticate(User $user) { if ($user instanceof MyUser) { $this->logger->info(/* ... /); } // or alternatively if ( ! $user instanceof MyUser) { throw new \LogicException( '$user must be an instance of MyUser, ' .'other instances are not supported.' ); } } } Note:* PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case. Add the method to the interface: interface User { /** @return string / public function getPassword(); /* @return string / public function getDisplayName(); } Loading history... Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report It seems like you code against a concrete implementation and not the interface `Zend_View_Interface` as the method `url()` does only exist in the following implementations of said interface: `Zend_View`. Let’s take a look at an example: interface User { /* @return string / public function getPassword(); } class MyUser implements User { public function getPassword() { // return something } public function getDisplayName() { // return some name. } } class AuthSystem { public function authenticate(User $user) { $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName())); // do something. } } In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break. Available Fixes Change the type-hint for the parameter: class AuthSystem { public function authenticate(MyUser $user) { / ... / } } Add an additional type-check: class AuthSystem { public function authenticate(User $user) { if ($user instanceof MyUser) { $this->logger->info(/* ... /); } // or alternatively if ( ! $user instanceof MyUser) { throw new \LogicException( '$user must be an instance of MyUser, ' .'other instances are not supported.' ); } } } Note:* PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case. Add the method to the interface: interface User { /** @return string / public function getPassword(); /* @return string */ public function getDisplayName(); } Loading history...
58	1		&& strpos($referrer, $this->view->serverUrl() . $this->view->url(['controller' => 'user', 'action' => 'logout'])) !== 0) {
			2 ignored issues – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report It seems like you code against a concrete implementation and not the interface `Zend_View_Interface` as the method `serverUrl()` does only exist in the following implementations of said interface: `Zend_View`. Let’s take a look at an example: interface User { /** @return string / public function getPassword(); } class MyUser implements User { public function getPassword() { // return something } public function getDisplayName() { // return some name. } } class AuthSystem { public function authenticate(User $user) { $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName())); // do something. } } In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break. Available Fixes Change the type-hint for the parameter: class AuthSystem { public function authenticate(MyUser $user) { / ... / } } Add an additional type-check: class AuthSystem { public function authenticate(User $user) { if ($user instanceof MyUser) { $this->logger->info(/* ... /); } // or alternatively if ( ! $user instanceof MyUser) { throw new \LogicException( '$user must be an instance of MyUser, ' .'other instances are not supported.' ); } } } Note:* PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case. Add the method to the interface: interface User { /** @return string / public function getPassword(); /* @return string / public function getDisplayName(); } Loading history... Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report It seems like you code against a concrete implementation and not the interface `Zend_View_Interface` as the method `url()` does only exist in the following implementations of said interface: `Zend_View`. Let’s take a look at an example: interface User { /* @return string / public function getPassword(); } class MyUser implements User { public function getPassword() { // return something } public function getDisplayName() { // return some name. } } class AuthSystem { public function authenticate(User $user) { $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName())); // do something. } } In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break. Available Fixes Change the type-hint for the parameter: class AuthSystem { public function authenticate(MyUser $user) { / ... / } } Add an additional type-check: class AuthSystem { public function authenticate(User $user) { if ($user instanceof MyUser) { $this->logger->info(/* ... /); } // or alternatively if ( ! $user instanceof MyUser) { throw new \LogicException( '$user must be an instance of MyUser, ' .'other instances are not supported.' ); } } } Note:* PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case. Add the method to the interface: interface User { /** @return string / public function getPassword(); /* @return string */ public function getDisplayName(); } Loading history...
59			return $this->_redirect($values['referrer']);
			0 ignored issues – show Deprecated Code introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report The method `Zend_Controller_Action::_redirect()` has been deprecated with message: Deprecated as of Zend Framework 1.7. Use redirect() instead. This method has been deprecated. The supplier of the class has supplied an explanatory message. The explanatory message should give you some clue as to whether and when the method will be removed from the class and what other method or class to use instead. Loading history...
60			} else {
61	1		return $this->_helper->redirector('index', 'movie');
62			}
63			} else {
64			$this->_helper->FlashMessenger(['error' => 'Login failed.']);
65			}
66			}
67			} else {
68			$form->setDefaults([
69			'referrer' => $this->getRequest()->getServer('HTTP_REFERER'),
			1 ignored issue – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report It seems like you code against a specific sub-type and not the parent class `Zend_Controller_Request_Abstract` as the method `getServer()` does only exist in the following sub-classes of `Zend_Controller_Request_Abstract`: `Zend_Controller_Request_Apache404`, `Zend_Controller_Request_Http`, `Zend_Controller_Request_HttpTestCase`. Maybe you want to `instanceof` check for one of these explicitly? Let’s take a look at an example: abstract class User { /** @return string / abstract public function getPassword(); } class MyUser extends User { public function getPassword() { // return something } public function getDisplayName() { // return some name. } } class AuthSystem { public function authenticate(User $user) { $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName())); // do something. } } In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different sub-classes of User which does not have a getDisplayName() method, the code will break. Available Fixes Change the type-hint for the parameter: class AuthSystem { public function authenticate(MyUser $user) { / ... / } } Add an additional type-check: class AuthSystem { public function authenticate(User $user) { if ($user instanceof MyUser) { $this->logger->info(/* ... /); } // or alternatively if ( ! $user instanceof MyUser) { throw new \LogicException( '$user must be an instance of MyUser, ' .'other instances are not supported.' ); } } } Note:* PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case. Add the method to the parent class: abstract class User { /** @return string / abstract public function getPassword(); /* @return string */ abstract public function getDisplayName(); } Loading history...
70			]);
71			}
72
73			$this->view->form = $form;
			1 ignored issue – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report Accessing `form` on the interface `Zend_View_Interface` suggest that you code against a concrete implementation. How about adding an `instanceof` check? If you access a property on an interface, you most likely code against a concrete implementation of the interface. Available Fixes Adding an additional type check: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeInterface $object) { if ($object instanceof SomeClass) { $a = $object->a; } } Changing the type hint: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeClass $object) { $a = $object->a; } Loading history...
74			}
75
76	1		public function logoutAction()
77			{
78	1		\mQueue\Model\User::setCurrent(null);
79	1		}
80
81		View Code Duplication	public function viewAction()
			0 ignored issues – show Duplication introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report This method seems to be duplicated in your project. Duplicated code is one of the most pungent code smells. If you need to duplicate the same code in three or more different places, we strongly encourage you to look into extracting the code into a single class or operation. You can also find more detailed suggestions in the “Code” section of your repository. Loading history...
82			{
83			if ($this->getRequest()->getParam('id')) {
84			$this->view->user = \mQueue\Model\UserMapper::find($this->getRequest()->getParam('id'));
			1 ignored issue – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report Accessing `user` on the interface `Zend_View_Interface` suggest that you code against a concrete implementation. How about adding an `instanceof` check? If you access a property on an interface, you most likely code against a concrete implementation of the interface. Available Fixes Adding an additional type check: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeInterface $object) { if ($object instanceof SomeClass) { $a = $object->a; } } Changing the type hint: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeClass $object) { $a = $object->a; } Loading history...
85			} else {
86			$this->view->user = \mQueue\Model\User::getCurrent();
			1 ignored issue – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report Accessing `user` on the interface `Zend_View_Interface` suggest that you code against a concrete implementation. How about adding an `instanceof` check? If you access a property on an interface, you most likely code against a concrete implementation of the interface. Available Fixes Adding an additional type check: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeInterface $object) { if ($object instanceof SomeClass) { $a = $object->a; } } Changing the type hint: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeClass $object) { $a = $object->a; } Loading history...
87			}
88
89			if (!$this->view->user) {
			1 ignored issue – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report Accessing `user` on the interface `Zend_View_Interface` suggest that you code against a concrete implementation. How about adding an `instanceof` check? If you access a property on an interface, you most likely code against a concrete implementation of the interface. Available Fixes Adding an additional type check: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeInterface $object) { if ($object instanceof SomeClass) { $a = $object->a; } } Changing the type hint: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeClass $object) { $a = $object->a; } Loading history...
90			throw new Exception($this->view->translate('User not found'));
			1 ignored issue – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report It seems like you code against a concrete implementation and not the interface `Zend_View_Interface` as the method `translate()` does only exist in the following implementations of said interface: `Zend_View`. Let’s take a look at an example: interface User { /** @return string / public function getPassword(); } class MyUser implements User { public function getPassword() { // return something } public function getDisplayName() { // return some name. } } class AuthSystem { public function authenticate(User $user) { $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName())); // do something. } } In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break. Available Fixes Change the type-hint for the parameter: class AuthSystem { public function authenticate(MyUser $user) { / ... / } } Add an additional type-check: class AuthSystem { public function authenticate(User $user) { if ($user instanceof MyUser) { $this->logger->info(/* ... /); } // or alternatively if ( ! $user instanceof MyUser) { throw new \LogicException( '$user must be an instance of MyUser, ' .'other instances are not supported.' ); } } } Note:* PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case. Add the method to the interface: interface User { /** @return string / public function getPassword(); /* @return string */ public function getDisplayName(); } Loading history...
91			}
92
93			$this->view->userActivity = $this->_helper->createPaginator(\mQueue\Model\StatusMapper::getActivityQuery($this->view->user));
			2 ignored issues – show Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report Accessing `userActivity` on the interface `Zend_View_Interface` suggest that you code against a concrete implementation. How about adding an `instanceof` check? If you access a property on an interface, you most likely code against a concrete implementation of the interface. Available Fixes Adding an additional type check: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeInterface $object) { if ($object instanceof SomeClass) { $a = $object->a; } } Changing the type hint: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeClass $object) { $a = $object->a; } Loading history... Bug introduced 2016-03-14 20:04 UTC by Report Bug Copy Issue Report Accessing `user` on the interface `Zend_View_Interface` suggest that you code against a concrete implementation. How about adding an `instanceof` check? If you access a property on an interface, you most likely code against a concrete implementation of the interface. Available Fixes Adding an additional type check: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeInterface $object) { if ($object instanceof SomeClass) { $a = $object->a; } } Changing the type hint: interface SomeInterface { } class SomeClass implements SomeInterface { public $a; } function someFunction(SomeClass $object) { $a = $object->a; } Loading history...
94			}
95			}
96

PowerKiKi / mqueue

Push — master ( ca1336...ce2897 )

UserController::viewAction() A

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