Total Complexity | 5 |
Total Lines | 45 |
Duplicated Lines | 66.67 % |
Changes | 0 |
Duplicate code is one of the most pungent code smells. A rule that is often used is to re-structure code once it is duplicated in three or more places.
Common duplication problems, and corresponding solutions are:
1 | # Copyright Pincer 2021-Present |
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2 | # Full MIT License can be found in `LICENSE` at the project root. |
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3 | |||
4 | """sent when a channel is updated""" |
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5 | |||
6 | from ..core.dispatch import GatewayDispatch |
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7 | from ..objects import Channel |
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8 | from ..utils.conversion import construct_client_dict |
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9 | |||
10 | |||
11 | View Code Duplication | async def channel_update_middleware(self, payload: GatewayDispatch): |
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12 | """|coro| |
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13 | |||
14 | Middleware for ``on_channel_update`` event. |
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15 | |||
16 | Parameters |
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17 | ---------- |
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18 | self : :class:`Client` |
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19 | The current client/bot. |
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20 | |||
21 | payload : :class:`GatewayDispatch` |
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22 | The data received from the channel update event. |
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23 | |||
24 | |||
25 | Returns |
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26 | ------- |
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27 | Tuple[:class:`str`, List[:class:`~pincer.objects.channel.channel.Channel`]] |
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28 | ``on_channel_update`` and a ``Channel`` |
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29 | """ |
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30 | |||
31 | channel = Channel.from_dict(construct_client_dict(self, payload.data)) |
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32 | |||
33 | if channel.guild_id in self.guilds.keys(): |
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34 | guild = self.guilds[channel.guild_id] |
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35 | old = filter(lambda c: c.id == channel.id, guild.channels) |
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36 | if old: |
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37 | guild.channels.remove(old) |
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38 | guild.channels.append(channel) |
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39 | |||
40 | return "on_channel_update", [channel] |
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41 | |||
42 | |||
43 | def export(): |
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44 | return channel_update_middleware |
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45 |