Conditions | 1 |
Paths | 1 |
Total Lines | 17 |
Code Lines | 10 |
Lines | 0 |
Ratio | 0 % |
Changes | 1 | ||
Bugs | 0 | Features | 0 |
1 | <?php |
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19 | public function crear(array $array): Consulta |
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20 | { |
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21 | $consulta = new CrearConsulta; |
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22 | |||
23 | $conexion = new CrearConexionBaseDeDatos; |
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24 | |||
25 | $insert = new Insert( |
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26 | new Tabla($array['tabla']), |
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27 | new ValoresAInsertar( |
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28 | $array['valores'] |
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29 | ) |
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30 | ); |
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31 | |||
32 | return $consulta->crear(array( |
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33 | 'conexion' => $conexion->crear(array()), |
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34 | 'sql' => $insert->insert(), |
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35 | 'valores' => $array['valores'] |
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36 | )); |
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38 | } |
Let?s assume that you have a directory layout like this:
and let?s assume the following content of
Bar.php
:If both files
OtherDir/Foo.php
andSomeDir/Foo.php
are loaded in the same runtime, you will see a PHP error such as the following:PHP Fatal error: Cannot use SomeDir\Foo as Foo because the name is already in use in OtherDir/Foo.php
However, as
OtherDir/Foo.php
does not necessarily have to be loaded and the error is only triggered if it is loaded beforeOtherDir/Bar.php
, this problem might go unnoticed for a while. In order to prevent this error from surfacing, you must import the namespace with a different alias: