SubMenuFactory::__construct()   A
last analyzed

Complexity

Conditions 1
Paths 1

Size

Total Lines 12
Code Lines 8

Duplication

Lines 0
Ratio 0 %

Code Coverage

Tests 9
CRAP Score 1

Importance

Changes 0
Metric Value
c 0
b 0
f 0
dl 0
loc 12
ccs 9
cts 9
cp 1
rs 9.4285
cc 1
eloc 8
nc 1
nop 1
crap 1
1
<?php
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namespace Malezha\Menu\Factory;
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use Illuminate\Contracts\Container\Container;
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use Malezha\Menu\Contracts\Attributes;
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use Malezha\Menu\Contracts\Builder;
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use Malezha\Menu\Element\SubMenu;
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/**
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 * Class SubMenuFactory
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 * @package Malezha\Menu\Factory
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 * 
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 * @property Builder $builder
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 * @inheritdoc
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 */
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class SubMenuFactory extends LinkFactory
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{
18 6
    public function __construct(Container $container)
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    {
20 6
        parent::__construct($container);
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22 6
        $this->parameters['builder'] = $this->app->makeWith(Builder::class, [
0 ignored issues
show
Bug introduced by
It seems like you code against a concrete implementation and not the interface Illuminate\Contracts\Container\Container as the method makeWith() does only exist in the following implementations of said interface: Illuminate\Container\Container.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
23 6
            'container' => $this->app,
24 6
            'name' => 'submenu-' . spl_object_hash($this),
25 6
            'activeAttributes' => $this->app->makeWith(Attributes::class, ['attributes' => []]),
0 ignored issues
show
Bug introduced by
It seems like you code against a concrete implementation and not the interface Illuminate\Contracts\Container\Container as the method makeWith() does only exist in the following implementations of said interface: Illuminate\Container\Container.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
26 6
            'attributes' => $this->app->makeWith(Attributes::class, ['attributes' => []]),
0 ignored issues
show
Bug introduced by
It seems like you code against a concrete implementation and not the interface Illuminate\Contracts\Container\Container as the method makeWith() does only exist in the following implementations of said interface: Illuminate\Container\Container.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
27
        ]);
28 6
        $this->parameters['view'] = $this->getElementConfig(SubMenu::class)['view'];
29 6
    }
30
31
    /**
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     * @param array $parameters
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     * @return SubMenu
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     */
35 6
    public function build($parameters = [])
36
    {
37 6
        $subMenu = $this->app->makeWith(SubMenu::class, $this->mergeParameters($parameters));
0 ignored issues
show
Bug introduced by
It seems like you code against a concrete implementation and not the interface Illuminate\Contracts\Container\Container as the method makeWith() does only exist in the following implementations of said interface: Illuminate\Container\Container.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
38 6
        $this->setDisplayRule($subMenu);
39
        
40 6
        return $subMenu;
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    }
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}