Completed
Pull Request — master (#2737)
by Jeroen
10:25
created

CreateUserCommand::__construct()   B

Complexity

Conditions 6
Paths 4

Size

Total Lines 25

Duplication

Lines 0
Ratio 0 %

Code Coverage

Tests 0
CRAP Score 42

Importance

Changes 0
Metric Value
dl 0
loc 25
ccs 0
cts 15
cp 0
rs 8.8977
c 0
b 0
f 0
cc 6
nc 4
nop 4
crap 42
1
<?php
2
3
namespace Kunstmaan\AdminBundle\Command;
4
5
use Doctrine\ORM\EntityManagerInterface;
6
use FOS\UserBundle\Model\GroupManager as FOSGroupManager;
7
use Kunstmaan\AdminBundle\Entity\Group;
8
use Kunstmaan\AdminBundle\Service\GroupManager;
9
use Symfony\Bundle\FrameworkBundle\Command\ContainerAwareCommand;
10
use Symfony\Component\Console\Exception\InvalidArgumentException;
11
use Symfony\Component\Console\Input\ArrayInput;
12
use Symfony\Component\Console\Input\InputArgument;
13
use Symfony\Component\Console\Input\InputInterface;
14
use Symfony\Component\Console\Input\InputOption;
15
use Symfony\Component\Console\Output\OutputInterface;
16
use Symfony\Component\Console\Question\ChoiceQuestion;
17
use Symfony\Component\Console\Question\Question;
18
19
/**
20
 * Symfony CLI command to create a user using bin/console kuma:user:create <username_of_the_user>
21
 *
22
 * @final since 5.1
23
 * NEXT_MAJOR extend from `Command` and remove `$this->getContainer` usages
24
 */
25
class CreateUserCommand extends ContainerAwareCommand
0 ignored issues
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Deprecated Code introduced by
The class Symfony\Bundle\Framework...d\ContainerAwareCommand has been deprecated with message: since Symfony 4.2, use {@see Command} instead.

This class, trait or interface has been deprecated. The supplier of the file has supplied an explanatory message.

The explanatory message should give you some clue as to whether and when the type will be removed from the class and what other constant to use instead.

Loading history...
26
{
27
    /** @var array */
28
    protected $groups = [];
29
    /** @var EntityManagerInterface */
30
    private $em;
31
    /** @var GroupManager */
32
    private $groupManager;
33
    /** @var string */
34
    private $userClassname;
35
    /** @var string */
36
    private $defaultLocale;
37
38
    public function __construct(/* EntityManagerInterface */ $em = null, /* GroupManager */ $groupManager = null, $userClassname = null, $defaultLocale = null)
39
    {
40
        parent::__construct();
41
42
        if (!$em instanceof EntityManagerInterface) {
43
            @trigger_error(sprintf('Passing a command name as the first argument of "%s" is deprecated since version symfony 3.4 and will be removed in symfony 4.0. If the command was registered by convention, make it a service instead. ', __METHOD__), E_USER_DEPRECATED);
0 ignored issues
show
Security Best Practice introduced by
It seems like you do not handle an error condition here. This can introduce security issues, and is generally not recommended.

If you suppress an error, we recommend checking for the error condition explicitly:

// For example instead of
@mkdir($dir);

// Better use
if (@mkdir($dir) === false) {
    throw new \RuntimeException('The directory '.$dir.' could not be created.');
}
Loading history...
44
45
            $this->setName(null === $em ? 'kuma:user:create' : $em);
46
47
            return;
48
        }
49
50
        if (!$groupManager instanceof GroupManager && !$groupManager instanceof FOSGroupManager) {
51
            throw new \InvalidArgumentException(sprintf('The "$groupManager" argument must be of type "%s" or type "%s"', GroupManager::class, FOSGroupManager::class));
52
        }
53
        if ($groupManager instanceof FOSGroupManager) {
54
            // NEXT_MAJOR set the groupmanager typehint to the kunstmaan groupmanager.
55
            @trigger_error(sprintf('Passing the groupmanager from FOSUserBundle as the first argument of "%s" is deprecated since KunstmaanAdminBundle 5.8 and will be removed in KunstmaanAdminBundle 6.0. Use the "%s" class instead.', __METHOD__, GroupManager::class), E_USER_DEPRECATED);
0 ignored issues
show
Security Best Practice introduced by
It seems like you do not handle an error condition here. This can introduce security issues, and is generally not recommended.

If you suppress an error, we recommend checking for the error condition explicitly:

// For example instead of
@mkdir($dir);

// Better use
if (@mkdir($dir) === false) {
    throw new \RuntimeException('The directory '.$dir.' could not be created.');
}
Loading history...
56
        }
57
58
        $this->em = $em;
59
        $this->groupManager = $groupManager;
0 ignored issues
show
Documentation Bug introduced by
It seems like $groupManager can also be of type object<FOS\UserBundle\Model\GroupManager>. However, the property $groupManager is declared as type object<Kunstmaan\AdminBu...e\Service\GroupManager>. Maybe add an additional type check?

Our type inference engine has found a suspicous assignment of a value to a property. This check raises an issue when a value that can be of a mixed type is assigned to a property that is type hinted more strictly.

For example, imagine you have a variable $accountId that can either hold an Id object or false (if there is no account id yet). Your code now assigns that value to the id property of an instance of the Account class. This class holds a proper account, so the id value must no longer be false.

Either this assignment is in error or a type check should be added for that assignment.

class Id
{
    public $id;

    public function __construct($id)
    {
        $this->id = $id;
    }

}

class Account
{
    /** @var  Id $id */
    public $id;
}

$account_id = false;

if (starsAreRight()) {
    $account_id = new Id(42);
}

$account = new Account();
if ($account instanceof Id)
{
    $account->id = $account_id;
}
Loading history...
60
        $this->userClassname = $userClassname;
61
        $this->defaultLocale = $defaultLocale;
62
    }
63
64
    protected function configure()
65
    {
66
        parent::configure();
67
68
        $this->setName('kuma:user:create')
69
            ->setDescription('Create a user.')
70
            ->setDefinition([
71
                new InputArgument('username', InputArgument::REQUIRED, 'The username'),
72
                new InputArgument('email', InputArgument::REQUIRED, 'The email'),
73
                new InputArgument('password', InputArgument::REQUIRED, 'The password'),
74
                new InputArgument('locale', InputArgument::OPTIONAL, 'The locale (language)'),
75
                new InputOption('group', null, InputOption::VALUE_REQUIRED, 'The group(s) the user should belong to'),
76
                new InputOption('super-admin', null, InputOption::VALUE_NONE, 'Set the user as super admin'),
77
                new InputOption('inactive', null, InputOption::VALUE_NONE, 'Set the user as inactive'),
78
            ])
79
            ->setHelp(<<<'EOT'
80
The <info>kuma:user:create</info> command creates a user:
81
82
  <info>php bin/console kuma:user:create matthieu --group=Users</info>
83
84
This interactive shell will ask you for an email and then a password.
85
86
You can alternatively specify the email, password and locale and group as extra arguments:
87
88
  <info>php bin/console kuma:user:create matthieu [email protected] mypassword en --group=Users</info>
89
90
You can create a super admin via the super-admin flag:
91
92
  <info>php bin/console kuma:user:create admin --super-admin --group=Administrators</info>
93
94
You can create an inactive user (will not be able to log in):
95
96
  <info>php bin/console kuma:user:create thibault --inactive --group=Users</info>
97
98
<comment>Note:</comment> You have to specify at least one group.
99
100
EOT
101
            );
102
    }
103
104
    protected function initialize(InputInterface $input, OutputInterface $output)
105
    {
106
        $this->groups = $this->getGroups();
107
    }
108
109
    /**
110
     * Executes the current command.
111
     *
112
     * @param InputInterface  $input  The input
113
     * @param OutputInterface $output The output
114
     *
115
     * @return int
116
     */
117
    protected function execute(InputInterface $input, OutputInterface $output)
118
    {
119
        if (null === $this->em) {
120
            $this->em = $this->getContainer()->get('doctrine.orm.entity_manager');
121
            $this->groupManager = $this->getContainer()->get('kunstmaan_admin.group_manager');
122
            $this->userClassname = $this->getContainer()->getParameter('kunstmaan_admin.user_class');
123
            $this->defaultLocale = $this->getContainer()->getParameter('kunstmaan_admin.default_admin_locale');
124
        }
125
126
        $username = $input->getArgument('username');
127
        $email = $input->getArgument('email');
128
        $password = $input->getArgument('password');
129
        $locale = $input->getArgument('locale');
130
        $superAdmin = $input->getOption('super-admin');
131
        $inactive = $input->getOption('inactive');
132
        $groupOption = $input->getOption('group');
133
134
        if (null === $locale) {
135
            $locale = $this->defaultLocale;
136
        }
137
        $command = $this->getApplication()->find('fos:user:create');
138
        $arguments = [
139
            'command' => 'fos:user:create',
140
            'username' => $username,
141
            'email' => $email,
142
            'password' => $password,
143
            '--super-admin' => $superAdmin,
144
            '--inactive' => $inactive,
145
        ];
146
147
        $input = new ArrayInput($arguments);
148
        $command->run($input, $output);
149
150
        // Fetch user that was just created
151
        $user = $this->em->getRepository($this->userClassname)->findOneBy(['username' => $username]);
152
153
        // Attach groups
154
        $groupOutput = [];
155
156
        foreach (explode(',', $groupOption) as $groupId) {
157
            if ((int) $groupId === 0) {
158
                foreach ($this->groups as $value) {
159
                    if ($groupId === $value->getName()) {
160
                        $group = $value;
161
162
                        break;
163
                    }
164
                }
165
            } else {
166
                $group = $this->groups[$groupId];
167
            }
168
169
            if (isset($group) && $group instanceof Group) {
170
                $groupOutput[] = $group->getName();
171
                $user->getGroups()->add($group);
172
            } else {
173
                throw new \RuntimeException('The selected group(s) can\'t be found.');
174
            }
175
        }
176
177
        // Set admin interface locale and enable password changed
178
        $user->setAdminLocale($locale);
179
        $user->setPasswordChanged(true);
180
181
        // Persist
182
        $this->em->persist($user);
183
        $this->em->flush();
184
185
        $output->writeln(sprintf('Added user <comment>%s</comment> to groups <comment>%s</comment>', $input->getArgument('username'), implode(',', $groupOutput)));
186
187
        return 0;
188
    }
189
190
    /**
191
     * Interacts with the user.
192
     *
193
     * @param InputInterface  $input  The input
194
     * @param OutputInterface $output The output
195
     *
196
     * @throws \InvalidArgumentException
197
     */
198
    protected function interact(InputInterface $input, OutputInterface $output)
199
    {
200 View Code Duplication
        if (!$input->getArgument('username')) {
0 ignored issues
show
Duplication introduced by
This code seems to be duplicated across your project.

Duplicated code is one of the most pungent code smells. If you need to duplicate the same code in three or more different places, we strongly encourage you to look into extracting the code into a single class or operation.

You can also find more detailed suggestions in the “Code” section of your repository.

Loading history...
201
            $question = new Question('Please choose a username:');
202
            $question->setValidator(function ($username) {
203
                if (null === $username) {
204
                    throw new \InvalidArgumentException('Username can not be empty');
205
                }
206
207
                return $username;
208
            });
209
            $username = $this->getHelper('question')->ask(
0 ignored issues
show
Bug introduced by
It seems like you code against a concrete implementation and not the interface Symfony\Component\Console\Helper\HelperInterface as the method ask() does only exist in the following implementations of said interface: Sensio\Bundle\GeneratorB...d\Helper\QuestionHelper, Symfony\Component\Console\Helper\QuestionHelper, Symfony\Component\Consol...r\SymfonyQuestionHelper.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
210
                $input,
211
                $output,
212
                $question
213
            );
214
            $input->setArgument('username', $username);
215
        }
216
217 View Code Duplication
        if (!$input->getArgument('email')) {
0 ignored issues
show
Duplication introduced by
This code seems to be duplicated across your project.

Duplicated code is one of the most pungent code smells. If you need to duplicate the same code in three or more different places, we strongly encourage you to look into extracting the code into a single class or operation.

You can also find more detailed suggestions in the “Code” section of your repository.

Loading history...
218
            $question = new Question('Please choose an email:');
219
            $question->setValidator(function ($email) {
220
                if (null === $email) {
221
                    throw new \InvalidArgumentException('Email can not be empty');
222
                }
223
224
                return $email;
225
            });
226
            $email = $this->getHelper('question')->ask(
0 ignored issues
show
Bug introduced by
It seems like you code against a concrete implementation and not the interface Symfony\Component\Console\Helper\HelperInterface as the method ask() does only exist in the following implementations of said interface: Sensio\Bundle\GeneratorB...d\Helper\QuestionHelper, Symfony\Component\Console\Helper\QuestionHelper, Symfony\Component\Consol...r\SymfonyQuestionHelper.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
227
                $input,
228
                $output,
229
                $question
230
            );
231
            $input->setArgument('email', $email);
232
        }
233
234
        if (!$input->getArgument('password')) {
235
            $question = new Question('Please choose a password:');
236
            $question->setHidden(true);
237
            $question->setHiddenFallback(false);
238
            $question->setValidator(function ($password) {
239
                if (null === $password) {
240
                    throw new \InvalidArgumentException('Password can not be empty');
241
                }
242
243
                return $password;
244
            });
245
            $password = $this->getHelper('question')->ask(
0 ignored issues
show
Bug introduced by
It seems like you code against a concrete implementation and not the interface Symfony\Component\Console\Helper\HelperInterface as the method ask() does only exist in the following implementations of said interface: Sensio\Bundle\GeneratorB...d\Helper\QuestionHelper, Symfony\Component\Console\Helper\QuestionHelper, Symfony\Component\Consol...r\SymfonyQuestionHelper.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
246
                $input,
247
                $output,
248
                $question
249
            );
250
251
            $input->setArgument('password', $password);
252
        }
253
254
        if (!$input->getArgument('locale')) {
255
            $locale = $this->getHelper('question')->ask(
0 ignored issues
show
Bug introduced by
It seems like you code against a concrete implementation and not the interface Symfony\Component\Console\Helper\HelperInterface as the method ask() does only exist in the following implementations of said interface: Sensio\Bundle\GeneratorB...d\Helper\QuestionHelper, Symfony\Component\Console\Helper\QuestionHelper, Symfony\Component\Consol...r\SymfonyQuestionHelper.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
256
                $input,
257
                $output,
258
                new Question('Please enter the locale (or leave empty for default admin locale):')
259
            );
260
            $input->setArgument('locale', $locale);
261
        }
262
263
        if (!$input->getOption('group')) {
264
            $question = new ChoiceQuestion(
265
                'Please enter the group(s) the user should be a member of (multiple possible, separated by comma):',
266
                $this->groups,
267
                ''
268
            );
269
            $question->setMultiselect(true);
270
            $question->setValidator(function ($groupsInput) {
271
                if (!$this->groups) {
0 ignored issues
show
Bug Best Practice introduced by
The expression $this->groups of type array is implicitly converted to a boolean; are you sure this is intended? If so, consider using empty($expr) instead to make it clear that you intend to check for an array without elements.

This check marks implicit conversions of arrays to boolean values in a comparison. While in PHP an empty array is considered to be equal (but not identical) to false, this is not always apparent.

Consider making the comparison explicit by using empty(..) or ! empty(...) instead.

Loading history...
272
                    throw new \RuntimeException('No user group(s) could be found');
273
                }
274
275
                // Validate that the chosen group options exist in the available groups
276
                $groupNames = array_unique(explode(',', $groupsInput));
277
                if (\count(array_intersect_key(array_flip($groupNames), $this->groups)) !== \count($groupNames)) {
278
                    throw new InvalidArgumentException('You have chosen non existing group(s)');
279
                }
280
281
                if ($groupsInput === '') {
282
                    throw new \RuntimeException('Group(s) must be of type integer and can not be empty');
283
                }
284
285
                return $groupsInput;
286
            });
287
288
            // Group has to be imploded because $input->setOption expects a string
289
            $groups = $this->getHelper('question')->ask($input, $output, $question);
0 ignored issues
show
Bug introduced by
It seems like you code against a concrete implementation and not the interface Symfony\Component\Console\Helper\HelperInterface as the method ask() does only exist in the following implementations of said interface: Sensio\Bundle\GeneratorB...d\Helper\QuestionHelper, Symfony\Component\Console\Helper\QuestionHelper, Symfony\Component\Consol...r\SymfonyQuestionHelper.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
290
291
            $input->setOption('group', $groups);
292
        }
293
    }
294
295
    private function getGroups()
296
    {
297
        $groups = $this->groupManager->findGroups();
298
299
        // reindexing the array, using the db id as the key
300
        $newGroups = [];
301
        foreach ($groups as $group) {
302
            $newGroups[$group->getId()] = $group;
303
        }
304
305
        return $newGroups;
306
    }
307
}
308