FriendlyInitializer::supports()   A
last analyzed

Complexity

Conditions 1
Paths 1

Size

Total Lines 4
Code Lines 2

Duplication

Lines 0
Ratio 0 %

Importance

Changes 0
Metric Value
dl 0
loc 4
rs 10
c 0
b 0
f 0
cc 1
eloc 2
nc 1
nop 1
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<?php
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namespace Knp\FriendlyContexts\Context\Initializer;
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use Behat\Behat\Context\Initializer\ContextInitializer;
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use Behat\Behat\Context\Context as ContextInterface;
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use Symfony\Component\DependencyInjection\ContainerInterface;
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use Knp\FriendlyContexts\Context\Context;
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class FriendlyInitializer implements ContextInitializer
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{
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    protected $config;
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    protected $container;
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    public function __construct($config, ContainerInterface $container)
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    {
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        $this->config    = $config;
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        $this->container = $container;
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    }
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    public function supports($context)
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    {
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        return $context instanceof Context;
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    }
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    public function initializeContext(ContextInterface $context)
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    {
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        if (false === $this->supports($context)) {
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            return;
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        }
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        $context->initialize($this->config, $this->container);
0 ignored issues
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Bug introduced by
It seems like you code against a concrete implementation and not the interface Behat\Behat\Context\Context as the method initialize() does only exist in the following implementations of said interface: Knp\FriendlyContexts\Context\AliceContext, Knp\FriendlyContexts\Context\ApiContext, Knp\FriendlyContexts\Context\Context, Knp\FriendlyContexts\Context\EntityContext, Knp\FriendlyContexts\Context\PageContext, Knp\FriendlyContexts\Context\RawMinkContext, Knp\FriendlyContexts\Context\RawPageContext, Knp\FriendlyContexts\Context\TableContext.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
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    }
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}
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