| 1 | <?php |
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| 10 | class Access |
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| 11 | { |
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| 12 | /** |
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| 13 | * Get the currently authenticated user or null. |
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| 14 | */ |
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| 15 | public function user() |
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| 19 | |||
| 20 | /** |
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| 21 | * Return if the current session user is a guest or not. |
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| 22 | * |
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| 23 | * @return mixed |
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| 24 | */ |
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| 25 | public function guest() |
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| 26 | { |
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| 27 | return auth()->guest(); |
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| 28 | } |
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| 29 | |||
| 30 | /** |
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| 31 | * @return mixed |
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| 32 | */ |
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| 33 | public function logout() |
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| 34 | { |
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| 35 | return auth()->logout(); |
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| 36 | } |
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| 37 | |||
| 38 | /** |
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| 39 | * Get the currently authenticated user's id. |
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| 40 | * |
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| 41 | * @return mixed |
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| 42 | */ |
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| 43 | public function id() |
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| 47 | |||
| 48 | /** |
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| 49 | * @param Authenticatable $user |
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| 50 | * @param bool $remember |
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| 51 | */ |
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| 52 | public function login(Authenticatable $user, $remember = false) |
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| 56 | |||
| 57 | /** |
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| 58 | * @param $id |
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| 59 | * |
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| 60 | * @return mixed |
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| 61 | */ |
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| 62 | public function loginUsingId($id) |
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| 63 | { |
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| 64 | return auth()->loginUsingId($id); |
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| 65 | } |
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| 66 | |||
| 67 | /** |
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| 68 | * Return if the current session user is a logged in. |
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| 69 | * |
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| 70 | * @return mixed |
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| 71 | */ |
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| 72 | public function check() |
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| 76 | } |
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| 77 |
It seems like the method you are trying to call exists only in some of the possible types.
Let’s take a look at an example:
Available Fixes
Add an additional type-check:
Only allow a single type to be passed if the variable comes from a parameter: