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by Nicolas
10:29 queued 08:07
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Repositories/Cache/CacheTagDecorator.php (1 issue)

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<?php
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namespace Modules\Tag\Repositories\Cache;
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use Modules\Core\Repositories\Cache\BaseCacheDecorator;
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use Modules\Tag\Repositories\TagRepository;
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class CacheTagDecorator extends BaseCacheDecorator implements TagRepository
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{
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    public function __construct(TagRepository $tag)
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    {
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        parent::__construct();
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        $this->entityName = 'tag.tags';
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        $this->repository = $tag;
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    }
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    /**
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     * Get all the tags in the given namespace
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     * @param string $namespace
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     * @return \Illuminate\Database\Eloquent\Collection
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     */
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    public function allForNamespace($namespace)
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    {
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        return $this->cache
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            ->tags($this->entityName, 'global')
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            ->remember("{$this->locale}.{$this->entityName}.allForNamespace.{$namespace}", $this->cacheTime,
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                function () use ($namespace) {
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                    return $this->repository->allForNamespace($namespace);
1 ignored issue
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It seems like you code against a concrete implementation and not the interface Modules\Core\Repositories\BaseRepository as the method allForNamespace() does only exist in the following implementations of said interface: Modules\Tag\Repositories\Cache\CacheTagDecorator, Modules\Tag\Repositories...t\EloquentTagRepository.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
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                }
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            );
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    }
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}
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