| 1 | """ |
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| 2 | Project Euler Problem 14: Longest Collatz Sequence |
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| 3 | ================================================== |
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| 4 | |||
| 5 | .. module:: solutions.problem14 |
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| 6 | :synopsis: My solution to problem #14. |
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| 7 | |||
| 8 | The source code for this problem can be |
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| 9 | `found here <https://bitbucket.org/nekedome/project-euler/src/master/solutions/problem14.py>`_. |
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| 10 | |||
| 11 | Problem Statement |
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| 12 | ################# |
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| 13 | |||
| 14 | The following iterative sequence is defined for the set of positive integers: |
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| 15 | |||
| 16 | .. math:: |
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| 17 | |||
| 18 | n &\\rightarrow \\frac{n}{2} \\; \\; \\; & \\mbox{(n is even)} \\\\ |
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| 19 | n &\\rightarrow 3n + 1 \\; \\; \\; & \\mbox{(n is odd)} |
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| 20 | |||
| 21 | Using the rule above and starting with :math:`13`, we generate the following sequence: |
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| 22 | :math:`13 \\rightarrow 40 \\rightarrow 20 \\rightarrow 10 \\rightarrow 5 \\rightarrow 16 \\rightarrow 8` |
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| 23 | :math:`\\rightarrow 4 \\rightarrow 2 \\rightarrow 1` |
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| 24 | |||
| 25 | It can be seen that this sequence (starting at :math:`13` and finishing at :math:`1`) contains :math:`10` terms. |
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| 26 | Although it has not been proved yet (Collatz Problem), it is thought that all starting numbers finish at :math:`1`. |
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| 27 | |||
| 28 | Which starting number, under one million, produces the longest chain? |
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| 29 | |||
| 30 | .. note:: once the chain starts the terms are allowed to go above one million. |
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| 31 | |||
| 32 | Solution Discussion |
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| 33 | ################### |
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| 34 | |||
| 35 | This solution simply uses an exhaust coupled with memoisation to avoid re-computing the same value over and over. |
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| 36 | |||
| 37 | The search space is iterated, and any partial results (that may form the tail of subsequent sequences) will be cached |
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| 38 | along with the associated chain length. |
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| 39 | |||
| 40 | Upon completion, search for the largest chain. |
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| 41 | |||
| 42 | Solution Implementation |
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| 43 | ####################### |
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| 44 | |||
| 45 | .. literalinclude:: ../../solutions/problem14.py |
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| 46 | :language: python |
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| 47 | :lines: 50- |
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| 48 | """ |
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| 49 | |||
| 50 | from typing import Dict |
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| 51 | |||
| 52 | from lib.numbertheory import is_even |
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| 53 | |||
| 54 | |||
| 55 | def collatz(n: int, d: Dict[int, int]) -> int: |
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d does not conform to the argument naming conventions ((([a-z][a-z0-9_]{2,30})|(_[a-z0-9_]*))$).
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| 56 | """ Compute the Collatz sequence starting at :math:`n` |
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| 57 | |||
| 58 | The length of a Collatz sequence starting at :math:`n` can be computed by iterating the Collatz map until it reaches |
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| 59 | :math:`1`. While this would be sensible for a single :math:`n`, performing this for many values of :math:`n` will |
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| 60 | result in a lot of redundant calculations. |
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| 61 | |||
| 62 | Consider the following two overlapping Collatz sequence: |
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| 63 | |||
| 64 | .. math:: |
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| 65 | |||
| 66 | 64 \\rightarrow 32 \\rightarrow 16 \\rightarrow 8 \\rightarrow 4 \\rightarrow 2 \\rightarrow 1 \\\\ |
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| 67 | 10 \\rightarrow 5 \\rightarrow 16 \\rightarrow 8 \\rightarrow 4 \\rightarrow 2 \\rightarrow 1 |
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| 68 | |||
| 69 | Observe the coalescence of these two sequences when they both reach the value :math:`16`. These two sequences |
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| 70 | provide the lengths of Collatz sequences starting at: :math:`1,2,4,5,8,10,16,32` and :math:`64`. |
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| 71 | |||
| 72 | By caching all results as we go we can avoid re-computing the tail of any coalescing sequences. |
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| 73 | |||
| 74 | :param n: the start of the Collatz sequence |
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| 75 | :param d: a dictionary of existing solutions |
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| 76 | :return: the length of the Collatz sequence starting at :math:`n` |
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| 77 | |||
| 78 | .. note:: the dictionary :math:`d` will be updated with any partial results computed. |
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| 79 | """ |
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| 80 | |||
| 81 | try: |
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| 82 | return d[n] |
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| 83 | except KeyError: |
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| 84 | if is_even(n): |
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| 85 | d[n] = 1 + collatz(n // 2, d) |
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| 86 | else: |
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| 87 | d[n] = 1 + collatz(3 * n + 1, d) |
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| 88 | return d[n] |
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| 89 | |||
| 90 | |||
| 91 | def solve(): |
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| 92 | """ Compute the answer to Project Euler's problem #14 """ |
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| 93 | |||
| 94 | upper_bound = 1000000 # search limit |
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| 95 | |||
| 96 | # Apply the recursive to find the maximal length chain |
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| 97 | d = {1: 1} |
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d does not conform to the variable naming conventions ((([a-z][a-z0-9_]{2,30})|(_[a-z0-9_]*))$).
This check looks for invalid names for a range of different identifiers. You can set regular expressions to which the identifiers must conform if the defaults do not match your requirements. If your project includes a Pylint configuration file, the settings contained in that file take precedence. To find out more about Pylint, please refer to their site. Loading history...
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| 98 | for i in range(1, upper_bound, 1): |
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| 99 | collatz(i, d) |
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| 100 | |||
| 101 | # Identify the largest chain |
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| 102 | v = list(d.values()) |
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v does not conform to the variable naming conventions ((([a-z][a-z0-9_]{2,30})|(_[a-z0-9_]*))$).
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| 103 | k = list(d.keys()) |
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| 104 | answer = k[v.index(max(v))] |
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| 105 | |||
| 106 | return answer |
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| 107 | |||
| 108 | |||
| 109 | expected_answer = 837799 |
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| 110 |
This check looks for invalid names for a range of different identifiers.
You can set regular expressions to which the identifiers must conform if the defaults do not match your requirements.
If your project includes a Pylint configuration file, the settings contained in that file take precedence.
To find out more about Pylint, please refer to their site.