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"""
Project Euler Problem 16: Power Digit Sum
=========================================
.. module:: solutions.problem16
:synopsis: My solution to problem #16.
The source code for this problem can be
`found here <https://bitbucket.org/nekedome/project-euler/src/master/solutions/problem16.py>`_.
Problem Statement
#################
:math:`2^{15} = 32768` and the sum of its digits is :math:`3 + 2 + 7 + 6 + 8 = 26`.
What is the sum of the digits of the number :math:`2^{1000}`?
Solution Discussion
###################
Simply compute :math:`2^{1000}` using Python's arbitrary precision arithmetic and then compute the digital sum.
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Solution Implementation
#######################
.. literalinclude:: ../../solutions/problem16.py
:language: python
:lines: 31-
from lib.digital import digit_sum
def solve():
""" Compute the answer to Project Euler's problem #16 """
target = 2 ** 1000
answer = digit_sum(target)
return answer
expected_answer = 1366
expected_answer
(([A-Z_][A-Z0-9_]*)|(__.*__))$
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