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Push — master ( ba8ed9...770316 )
by Jeroen
06:11
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AdminBundle/Command/CreateUserCommand.php (11 issues)

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1
<?php
2
3
namespace Kunstmaan\AdminBundle\Command;
4
5
use Doctrine\ORM\EntityManagerInterface;
6
use FOS\UserBundle\Model\GroupManagerInterface;
7
use Kunstmaan\AdminBundle\Entity\Group;
8
use Symfony\Bundle\FrameworkBundle\Command\ContainerAwareCommand;
9
use Symfony\Component\Console\Input\ArrayInput;
10
use Symfony\Component\Console\Input\InputArgument;
11
use Symfony\Component\Console\Input\InputInterface;
12
use Symfony\Component\Console\Input\InputOption;
13
use Symfony\Component\Console\Output\OutputInterface;
14
use Symfony\Component\Console\Question\ChoiceQuestion;
15
use Symfony\Component\Console\Question\Question;
16
use Symfony\Component\Console\Exception\InvalidArgumentException;
17
18
/**
19
 * Symfony CLI command to create a user using bin/console kuma:user:create <username_of_the_user>
20
 *
21
 * @final since 5.1
22
 * NEXT_MAJOR extend from `Command` and remove `$this->getContainer` usages
23
 */
24
class CreateUserCommand extends ContainerAwareCommand
0 ignored issues
show
Deprecated Code introduced by
The class Symfony\Bundle\Framework...d\ContainerAwareCommand has been deprecated with message: since Symfony 4.2, use {@see Command} instead.

This class, trait or interface has been deprecated. The supplier of the file has supplied an explanatory message.

The explanatory message should give you some clue as to whether and when the type will be removed from the class and what other constant to use instead.

Loading history...
25
{
26
    /** @var EntityManagerInterface */
27
    private $em;
28
29
    /** @var GroupManagerInterface */
30
    private $groupManager;
31
32
    /** @var string */
33
    private $userClassname;
34
35
    /** @var string */
36
    private $defaultLocale;
37
38
    /** @var array */
39
    protected $groups = [];
40
41
    public function __construct(/* EntityManagerInterface */ $em = null, GroupManagerInterface $groupManager = null, $userClassname = null, $defaultLocale = null)
42
    {
43
        parent::__construct();
44
45
        if (!$em instanceof EntityManagerInterface) {
46
            @trigger_error(sprintf('Passing a command name as the first argument of "%s" is deprecated since version symfony 3.4 and will be removed in symfony 4.0. If the command was registered by convention, make it a service instead. ', __METHOD__), E_USER_DEPRECATED);
0 ignored issues
show
Security Best Practice introduced by
It seems like you do not handle an error condition here. This can introduce security issues, and is generally not recommended.

If you suppress an error, we recommend checking for the error condition explicitly:

// For example instead of
@mkdir($dir);

// Better use
if (@mkdir($dir) === false) {
    throw new \RuntimeException('The directory '.$dir.' could not be created.');
}
Loading history...
47
48
            $this->setName(null === $em ? 'kuma:user:create' : $em);
49
50
            return;
51
        }
52
53
        $this->em = $em;
54
        $this->groupManager = $groupManager;
55
        $this->userClassname = $userClassname;
56
        $this->defaultLocale = $defaultLocale;
57
    }
58
59
    protected function configure()
60
    {
61
        parent::configure();
62
63
        $this->setName('kuma:user:create')
64
            ->setDescription('Create a user.')
65
            ->setDefinition(array(
66
                new InputArgument('username', InputArgument::REQUIRED, 'The username'),
67
                new InputArgument('email', InputArgument::REQUIRED, 'The email'),
68
                new InputArgument('password', InputArgument::REQUIRED, 'The password'),
69
                new InputArgument('locale', InputArgument::OPTIONAL, 'The locale (language)'),
70
                new InputOption('group', null, InputOption::VALUE_REQUIRED, 'The group(s) the user should belong to'),
71
                new InputOption('super-admin', null, InputOption::VALUE_NONE, 'Set the user as super admin'),
72
                new InputOption('inactive', null, InputOption::VALUE_NONE, 'Set the user as inactive'),
73
            ))
74
            ->setHelp(<<<'EOT'
75
The <info>kuma:user:create</info> command creates a user:
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77
  <info>php bin/console kuma:user:create matthieu --group=Users</info>
78
79
This interactive shell will ask you for an email and then a password.
80
81
You can alternatively specify the email, password and locale and group as extra arguments:
82
83
  <info>php bin/console kuma:user:create matthieu [email protected] mypassword en --group=Users</info>
84
85
You can create a super admin via the super-admin flag:
86
87
  <info>php bin/console kuma:user:create admin --super-admin --group=Administrators</info>
88
89
You can create an inactive user (will not be able to log in):
90
91
  <info>php bin/console kuma:user:create thibault --inactive --group=Users</info>
92
93
<comment>Note:</comment> You have to specify at least one group.
94
95
EOT
96
            );
97
    }
98
99
    protected function initialize(InputInterface $input, OutputInterface $output)
100
    {
101
        $this->groups = $this->getGroups();
102
    }
103
104
    /**
105
     * Executes the current command.
106
     *
107
     * @param InputInterface  $input  The input
108
     * @param OutputInterface $output The output
109
     *
110
     * @return int
0 ignored issues
show
Should the return type not be integer|null?

This check compares the return type specified in the @return annotation of a function or method doc comment with the types returned by the function and raises an issue if they mismatch.

Loading history...
111
     */
112
    protected function execute(InputInterface $input, OutputInterface $output)
113
    {
114
        if (null === $this->em) {
115
            $this->em = $this->getContainer()->get('doctrine.orm.entity_manager');
116
            $this->groupManager = $this->getContainer()->get('fos_user.group_manager');
117
            $this->userClassname = $this->getContainer()->getParameter('fos_user.model.user.class');
118
            $this->defaultLocale = $this->getContainer()->getParameter('kunstmaan_admin.default_admin_locale');
119
        }
120
121
        $username = $input->getArgument('username');
122
        $email = $input->getArgument('email');
123
        $password = $input->getArgument('password');
124
        $locale = $input->getArgument('locale');
125
        $superAdmin = $input->getOption('super-admin');
126
        $inactive = $input->getOption('inactive');
127
        $groupOption = $input->getOption('group');
128
129
        if (null === $locale) {
130
            $locale = $this->defaultLocale;
131
        }
132
        $command = $this->getApplication()->find('fos:user:create');
133
        $arguments = array(
134
            'command' => 'fos:user:create',
135
            'username' => $username,
136
            'email' => $email,
137
            'password' => $password,
138
            '--super-admin' => $superAdmin,
139
            '--inactive' => $inactive,
140
        );
141
142
        $input = new ArrayInput($arguments);
143
        $command->run($input, $output);
144
145
        // Fetch user that was just created
146
        $user = $this->em->getRepository($this->userClassname)->findOneBy(array('username' => $username));
147
148
        // Attach groups
149
        $groupOutput = [];
150
151
        foreach (explode(',', $groupOption) as $groupId) {
152
            if ((int) $groupId === 0) {
153
                foreach ($this->groups as $value) {
154
                    if ($groupId === $value->getName()) {
155
                        $group = $value;
156
157
                        break;
158
                    }
159
                }
160
            } else {
161
                $group = $this->groups[$groupId];
162
            }
163
164
            if (isset($group) && $group instanceof Group) {
165
                $groupOutput[] = $group->getName();
166
                $user->getGroups()->add($group);
167
            } else {
168
                throw new \RuntimeException(
169
                    'The selected group(s) can\'t be found.'
170
                );
171
            }
172
        }
173
174
        // Set admin interface locale and enable password changed
175
        $user->setAdminLocale($locale);
176
        $user->setPasswordChanged(true);
177
178
        // Persist
179
        $this->em->persist($user);
180
        $this->em->flush();
181
182
        $output->writeln(sprintf('Added user <comment>%s</comment> to groups <comment>%s</comment>', $input->getArgument('username'), implode(',', $groupOutput)));
183
    }
184
185
    /**
186
     * Interacts with the user.
187
     *
188
     * @param InputInterface  $input  The input
189
     * @param OutputInterface $output The output
190
     *
191
     * @throws \InvalidArgumentException
192
     */
193
    protected function interact(InputInterface $input, OutputInterface $output)
194
    {
195 View Code Duplication
        if (!$input->getArgument('username')) {
0 ignored issues
show
This code seems to be duplicated across your project.

Duplicated code is one of the most pungent code smells. If you need to duplicate the same code in three or more different places, we strongly encourage you to look into extracting the code into a single class or operation.

You can also find more detailed suggestions in the “Code” section of your repository.

Loading history...
196
            $question = new Question('Please choose a username:');
197
            $question->setValidator(function ($username) {
198
                if (null === $username) {
199
                    throw new \InvalidArgumentException('Username can not be empty');
200
                }
201
202
                return $username;
203
            });
204
            $username = $this->getHelper('question')->ask(
0 ignored issues
show
It seems like you code against a concrete implementation and not the interface Symfony\Component\Console\Helper\HelperInterface as the method ask() does only exist in the following implementations of said interface: Sensio\Bundle\GeneratorB...d\Helper\QuestionHelper, Symfony\Component\Console\Helper\QuestionHelper, Symfony\Component\Consol...r\SymfonyQuestionHelper.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
205
                $input,
206
                $output,
207
                $question
208
            );
209
            $input->setArgument('username', $username);
210
        }
211
212 View Code Duplication
        if (!$input->getArgument('email')) {
0 ignored issues
show
This code seems to be duplicated across your project.

Duplicated code is one of the most pungent code smells. If you need to duplicate the same code in three or more different places, we strongly encourage you to look into extracting the code into a single class or operation.

You can also find more detailed suggestions in the “Code” section of your repository.

Loading history...
213
            $question = new Question('Please choose an email:');
214
            $question->setValidator(function ($email) {
215
                if (null === $email) {
216
                    throw new \InvalidArgumentException('Email can not be empty');
217
                }
218
219
                return $email;
220
            });
221
            $email = $this->getHelper('question')->ask(
0 ignored issues
show
It seems like you code against a concrete implementation and not the interface Symfony\Component\Console\Helper\HelperInterface as the method ask() does only exist in the following implementations of said interface: Sensio\Bundle\GeneratorB...d\Helper\QuestionHelper, Symfony\Component\Console\Helper\QuestionHelper, Symfony\Component\Consol...r\SymfonyQuestionHelper.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
222
                $input,
223
                $output,
224
                $question
225
            );
226
            $input->setArgument('email', $email);
227
        }
228
229
        if (!$input->getArgument('password')) {
230
            $question = new Question('Please choose a password:');
231
            $question->setHidden(true);
232
            $question->setHiddenFallback(false);
233
            $question->setValidator(function ($password) {
234
                if (null === $password) {
235
                    throw new \InvalidArgumentException('Password can not be empty');
236
                }
237
238
                return $password;
239
            });
240
            $password = $this->getHelper('question')->ask(
0 ignored issues
show
It seems like you code against a concrete implementation and not the interface Symfony\Component\Console\Helper\HelperInterface as the method ask() does only exist in the following implementations of said interface: Sensio\Bundle\GeneratorB...d\Helper\QuestionHelper, Symfony\Component\Console\Helper\QuestionHelper, Symfony\Component\Consol...r\SymfonyQuestionHelper.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
241
                $input,
242
                $output,
243
                $question
244
            );
245
246
            $input->setArgument('password', $password);
247
        }
248
249
        if (!$input->getArgument('locale')) {
250
            $locale = $this->getHelper('question')->ask(
0 ignored issues
show
It seems like you code against a concrete implementation and not the interface Symfony\Component\Console\Helper\HelperInterface as the method ask() does only exist in the following implementations of said interface: Sensio\Bundle\GeneratorB...d\Helper\QuestionHelper, Symfony\Component\Console\Helper\QuestionHelper, Symfony\Component\Consol...r\SymfonyQuestionHelper.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
251
                $input,
252
                $output,
253
                new Question('Please enter the locale (or leave empty for default admin locale):')
254
            );
255
            $input->setArgument('locale', $locale);
256
        }
257
258
        if (!$input->getOption('group')) {
259
            $question = new ChoiceQuestion(
260
                'Please enter the group(s) the user should be a member of (multiple possible, separated by comma):',
261
                $this->groups,
262
                ''
263
            );
264
            $question->setMultiselect(true);
265
            $question->setValidator(function ($groupsInput) {
266
                if (!$this->groups) {
0 ignored issues
show
Bug Best Practice introduced by
The expression $this->groups of type array is implicitly converted to a boolean; are you sure this is intended? If so, consider using empty($expr) instead to make it clear that you intend to check for an array without elements.

This check marks implicit conversions of arrays to boolean values in a comparison. While in PHP an empty array is considered to be equal (but not identical) to false, this is not always apparent.

Consider making the comparison explicit by using empty(..) or ! empty(...) instead.

Loading history...
267
                    throw new \RuntimeException('No user group(s) could be found');
268
                }
269
270
                // Validate that the chosen group options exist in the available groups
271
                $groupNames = array_unique(explode(',', $groupsInput));
272
                if (count(array_intersect_key(array_flip($groupNames), $this->groups)) !== count($groupNames)) {
273
                    throw new InvalidArgumentException('You have chosen non existing group(s)');
274
                }
275
276
                if ($groupsInput === '') {
277
                    throw new \RuntimeException(
278
                        'Group(s) must be of type integer and can not be empty'
279
                    );
280
                }
281
282
                return $groupsInput;
283
            });
284
285
            // Group has to be imploded because $input->setOption expects a string
286
            $groups = $this->getHelper('question')->ask($input, $output, $question);
0 ignored issues
show
It seems like you code against a concrete implementation and not the interface Symfony\Component\Console\Helper\HelperInterface as the method ask() does only exist in the following implementations of said interface: Sensio\Bundle\GeneratorB...d\Helper\QuestionHelper, Symfony\Component\Console\Helper\QuestionHelper, Symfony\Component\Consol...r\SymfonyQuestionHelper.

Let’s take a look at an example:

interface User
{
    /** @return string */
    public function getPassword();
}

class MyUser implements User
{
    public function getPassword()
    {
        // return something
    }

    public function getDisplayName()
    {
        // return some name.
    }
}

class AuthSystem
{
    public function authenticate(User $user)
    {
        $this->logger->info(sprintf('Authenticating %s.', $user->getDisplayName()));
        // do something.
    }
}

In the above example, the authenticate() method works fine as long as you just pass instances of MyUser. However, if you now also want to pass a different implementation of User which does not have a getDisplayName() method, the code will break.

Available Fixes

  1. Change the type-hint for the parameter:

    class AuthSystem
    {
        public function authenticate(MyUser $user) { /* ... */ }
    }
    
  2. Add an additional type-check:

    class AuthSystem
    {
        public function authenticate(User $user)
        {
            if ($user instanceof MyUser) {
                $this->logger->info(/** ... */);
            }
    
            // or alternatively
            if ( ! $user instanceof MyUser) {
                throw new \LogicException(
                    '$user must be an instance of MyUser, '
                   .'other instances are not supported.'
                );
            }
    
        }
    }
    
Note: PHP Analyzer uses reverse abstract interpretation to narrow down the types inside the if block in such a case.
  1. Add the method to the interface:

    interface User
    {
        /** @return string */
        public function getPassword();
    
        /** @return string */
        public function getDisplayName();
    }
    
Loading history...
287
288
            $input->setOption('group', $groups);
289
        }
290
    }
291
292
    private function getGroups()
293
    {
294
        $groups = $this->groupManager->findGroups();
295
296
        // reindexing the array, using the db id as the key
297
        $newGroups = [];
298
        foreach ($groups as $group) {
299
            $newGroups[$group->getId()] = $group;
300
        }
301
302
        return $newGroups;
303
    }
304
}
305